Given the following information: Li(s) → Li(g) Li(s) = 161 kJ/mol Heat of sublimation of HCI(g) → H(g) + CI(g) Bond energy of HCI = 427 kJ/mol %3D Li(g) → Li+(g) + e- lonization energy of Li(g) = 520. kJ/mol Cl(g) + e- → Cl-(g) CI(g) = -349 kJ/mol Electron affinity of %3D Li+(g) + Cl-(g) –→ LİCI(s) Lattice energy of LİCI(s) = -829 kJ/mol %3D H2(g) → 2H(g) Bond energy of H2 = 432 kJ/mol calculate the net change in energy for the reaction 2Li(s) + 2HCI(g) → 2LİCI(s) + H2(g)

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Chapter1: Chemical Foundations
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Given the following information:
Li(s) → Li(g)
Li(s) = 161 kJ/mol
Heat of sublimation of
HCI(g) → H(g) + Cl(g)
Bond energy of
HCI = 427 kJ/mol
Li(g) → Li+(g) + e-
lonization energy of
Li(g) = 520. kJ/mol
CI(g) + e- → CI-(g)
Electron affinity of
Cl(g) = -349 kJ/mol
Li+(g) + Cl-(g) →→ LiC(s)
Lattice energy of
LİCI(s) = -829 kJ/mol
H2(g) → 2H(g)
Bond energy of
H2 = 432 kJ/mol
calculate the net change in energy for the
reaction 2Li(s) + 2HCI(g) → 2LİCI(s) + H2(g)
-179 kJ
362 kJ
-70 kJ
-572 kJ
None
ese
Transcribed Image Text:Given the following information: Li(s) → Li(g) Li(s) = 161 kJ/mol Heat of sublimation of HCI(g) → H(g) + Cl(g) Bond energy of HCI = 427 kJ/mol Li(g) → Li+(g) + e- lonization energy of Li(g) = 520. kJ/mol CI(g) + e- → CI-(g) Electron affinity of Cl(g) = -349 kJ/mol Li+(g) + Cl-(g) →→ LiC(s) Lattice energy of LİCI(s) = -829 kJ/mol H2(g) → 2H(g) Bond energy of H2 = 432 kJ/mol calculate the net change in energy for the reaction 2Li(s) + 2HCI(g) → 2LİCI(s) + H2(g) -179 kJ 362 kJ -70 kJ -572 kJ None ese
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