Given the following information for water, H20 (at 1 atm), calculate the amount of heat in kJ needed (at 1 atm) to vaporize a 46.9-g sample of liquid water at its normal boiling point of 100 °C. boiling point = 100 °C AHvap(100 °C) = 40.7 kJ/mol %3D melting point = 0.00 °C AHfus(0.00 °C) = 6.01 kJ/mol %3D specific heat liquid = 4.18 J/g°C kJ

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Chapter1: Chemical Foundations
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Calčulate the energy change during a pha change.
Given the following information for water, H,0 (at 1 atm), calculate the amount of heat in kJ needed (at 1
atm) to vaporize a 46.9-g sample of liquid water at its normal boiling point of 100 °C.
AHvap(100 °C) = 40.7 kJ/mol
AHfus (0.00 °C) = 6.01 kJ/mol
boiling point = 100 °C
%3D
melting point = 0.00 °C
specific heat liquid = 4.18 J/g°C
kJ
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We now have the tools needed to calculate both the amount of thermal energy required to warm an object
in a particular physical state and the amount of thermal energy required to change the physical state of a
substance. Interactive Figure 5.3.6 shows the energy involved in heating 100-g samples of benzene and
water over a large temperature range.
26
tv
A hulu
W
Transcribed Image Text:Calčulate the energy change during a pha change. Given the following information for water, H,0 (at 1 atm), calculate the amount of heat in kJ needed (at 1 atm) to vaporize a 46.9-g sample of liquid water at its normal boiling point of 100 °C. AHvap(100 °C) = 40.7 kJ/mol AHfus (0.00 °C) = 6.01 kJ/mol boiling point = 100 °C %3D melting point = 0.00 °C specific heat liquid = 4.18 J/g°C kJ Check & Submit Answer Show Approach We now have the tools needed to calculate both the amount of thermal energy required to warm an object in a particular physical state and the amount of thermal energy required to change the physical state of a substance. Interactive Figure 5.3.6 shows the energy involved in heating 100-g samples of benzene and water over a large temperature range. 26 tv A hulu W
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