Given the following data: B. Compact Unit Weight Determination Fine Aggregate a. Weight of measure, g. 300.00 b. Weight of measure + sample, g. 8,820.00 c. Weight of sample, g. (b) – (a) d. Volume of measure, cm e. Unit weight, g/cm 1.019 Determine the diameter in cm of the bucket if V=3.1416(d) (21.23)/4. Continues computation and write your answer in 2 decimal places O 22.39 О 32.29 O 23.92 O None of the abovel O 23.29

Given the following data: B. Compact Unit Weight Determination Fine Aggregate a. Weight of measure, g. 300.00 b. Weight of measure + sample, g. 8,820.00 c. Weight of sample, g. (b) – (a) d. Volume of measure, cm e. Unit weight, g/cm 1.019 Determine the diameter in cm of the bucket if V=3.1416(d) (21.23)/4. Continues computation and write your answer in 2 decimal places O 22.39 О 32.29 O 23.92 O None of the abovel O 23.29

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained:Volume of bucket = 14 LWeight of empty bucket = 9.21 kgWeight of bucket filled with dry rodded coarse aggregate:Trial 1 = 34.75 kgTrial 2 = 34.06 kgMeasureSampleA B CWet Mass (g) 521.0 522.4 523.4Dry Mass (g) 491.6 491.7 492.1Absorption (%) 2.5 2.4 2.3Table P 5 . 9 determine the amount of water required to increase the moisture content of aggregate to reach absorption?5.9 Three samples of fine aggregate have the properties shown in Table Trial 3 = 35.74 kga. Calculate the average dry-rodded unit weightb. If the bulk dry specific gravity of the aggregate is 2.620, calculate thepercent voids between aggregate particles for each trial.
For the solution for this problem, I was wondering how they got 0.75s and the 0.25 in the graph? I thought in the muller method you replace the point of interest with 1 unit load up? Can you please show all calculations so I can see where the 0.75s and 0.25 are coming from
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