c. Find the p-value.O 0.05 Picture p-value < 0.10O 0.025 Picture p-value < 0.05O 0.01Picture p-value < 0.025O p-value < 0.01O pvalue Picture 0.10d. What is your conclusion?O Reject Hg, we can conclude that the two categories are dependent.O Do not reject Hg, we can conclude that the two categories are dependent.O Reject He, We cannot conclude that the two categories are dependent.O Do not reject Hg, we cannot conclude that the two categories are dependent. Given the following contingency table, conduct a test for independence at the 10% significance level. (You may find it useful toreference the appropriate table: chi-square table or F table)Variable AVariable B1374324464a. Choose the null and alternative hypotheses.O Hg: The two variables are independent.; H4: The two variables are dependent.O Họ: The two variables are dependent.; HA: The two variables are independent.b. Calculate the value of the test statistic. (Round intermediate calculations to at least 4 decimal places and final answer to 3decimal places.)Test statistic

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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3) Examine your t-test score in the paired samples t-test table. Is the p value significant? State in one to two sentences whether the test was significant and interpret this result.
Test the claim that the proportion of men who own cats is smaller than the proportion of women who own cats at the .025 significance level. The null and alternative hypothesis would be: Ho MMF Ho: PM = PF H₁: MMF O H₁: PM > PF O The test is: two-tailed right-tailed O The test statistic is: Based on a sample of 60 men, 25% owned cats Based on a sample of 40 women, 40% owned cats The p-value is: Ho: M = μF H₁: UM
A poll of 2,122 randomly selected adults showed that 93% of them own cell phones. The technology display below results from a test of the claim that 92% of adults own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.05 significance level to complete parts (a) through (e). Test of p = 0.92 vs p *0.92 Sample X 1 N 2,122 1970 Sample p 0.928369 95% CI The P-value is (Round to three decimal places as needed.) (0.917397,0.939341) a. Is the test two-tailed, left-tailed, or right-tailed? O Two-tailed test O Left-tailed test O Right tailed test b. What is the test statistic? The test statistic is (Round to two decimal places as needed.) c. What is the P-value? Z-Value 1.42 P-Value 0.155
The agriculture extension office wants to test the claim that GMO carrots are longer than Organic carrots. What kind of hypotheisis test is this? O 1 Proportion z-test 2 Proportions z-test 1 Mean t-test 2 Means Matched Pairs t-test 2 Independent Means t-test Which hypotheses do we want to test? O Họ: H1 = H2 HẠ: H1= H2 O Họ: H1 = H2 HA: H1 = H2 O Ho: H1 = H2 HA: H1> H2 O Ho: H1 = H2 HA: H1< H2
Tne roilowing tapie contains tne scores rom a group or 1ɔ nign scnooi seniors on a psycnoiogicai assessment or positive arrect ror tne supject or matn ana tneir scores on the same assessment for the subject of chemistry. The assessment measures the strength of the student's positive feelings towards the subject on a 40-point scale, with 40 being the most positive. Positive Affect Assessment Score for Math Assessment, x Score for Chemistry Assessment, y 25 20 31 24 7 10 31 25 10 4 8 27 26 9 8 10 9 9 29 28 16 17 23 17 26 14 40 28 Copy Data Step 1 of 2: Calculate the sum of squared errors, SSE, based on a regression analysis of the assessment data. Round your answer to two decimal places, if necessary.
The mean price of mid-sized cars in a region is $57,600. A test is conducted to see if the claim is true. Identify the null hypothesis. ? v? v Identify the alternative hypothesis. ? v:?v| ? v Identify the type I error. O You decide that the mean price of mid-sized cars is not $57,600, when the mean price of mid- sized cars actually is $57,600. O You decide that the mean price of mid-sized cars is $57,600, when the mean price of mid- sized cars actually is not $57,600. O You decide that the mean price of mid-sized cars is not $57,600, when the mean price of mid- sized cars actually is nor $57,600. O You decide that the mean price of mid-sized cars is $57,600, when the mean price of mid- sized cars actually is $57,600. Identify the type II error. O You decide that the mean price of mid-sized cars is not $57,600, when the mean price of mid- sized cars actually is $57,600. O You decide that the mean price of mid-sized cars is $57,600, when the mean price of mid- sized cars actually is not…
Im confused on this problem
Help with Q4
need test statistics and p value
To test if TV preference and gender are independent, which hypothesis test would be used? a. 2 Prop Z Test b. Chi-square test c. ! Sample T test d. Linear Regression Test

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