Given the following Binary Tree, reverse the Tree as in the diagram below. Similarly, invert the tree (or turn upside down) and return to its root. The solution can be done using a Recursive method or function, or you can use an iterative method to combine both solutions within your code. /** * Definition for a binary tree node. * struct TreeNode { int val; TreeNode *left; TreeNode *right; TreeNode(): val(0), left(nullptr), right(nullptr) {} TreeNode(int x) : val(x), left(nullptr), right(nullptr) {} TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {} * * * * * * */ class Solution { public: 9 } TreeNode* invertTree(TreeNode* root) { }
Given the following Binary Tree, reverse the Tree as in the diagram below. Similarly, invert the tree (or turn upside down) and return to its root. The solution can be done using a Recursive method or function, or you can use an iterative method to combine both solutions within your code. /** * Definition for a binary tree node. * struct TreeNode { int val; TreeNode *left; TreeNode *right; TreeNode(): val(0), left(nullptr), right(nullptr) {} TreeNode(int x) : val(x), left(nullptr), right(nullptr) {} TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {} * * * * * * */ class Solution { public: 9 } TreeNode* invertTree(TreeNode* root) { }
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
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Please type in Java and provide explanations/comments about what the code is doing and why.
Psedeocode provided and can be worked off of.
Expert Solution
Step 1
Binary Tree :
A binary tree, also known as the left child and the right child, is a type of tree data structure used in computer science where each node can have up to two children.
Recursive Solution :
It is simple to recursively solve one of the most well-known interview questions. The plan is to move through the tree in a preorder approach, swapping each node's left and right child before recursively inverting its left and right subtree for each node that is encountered. The tree can also be navigated in a postorder method.
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