Given the following at 25°C and 1.00 atm: 1/2 N2 (g) + O2 (g) → NO2 (g) AHO = 33.2 kJ N2 (g) + 2 02 (g) → N204 (g) AH. = 11.1 kJ Calculate the AHº for the reaction below at 25°C. 2 NO2 (g) – N204 (g)

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Chapter1: Chemical Foundations
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Given the following at 25°C and 1.00 atm:

\[ \frac{1}{2} \text{N}_2 (g) + \text{O}_2 (g) \rightarrow \text{NO}_2 (g) \quad \Delta H^0 = 33.2 \text{ kJ} \]

\[ \text{N}_2 (g) + 2 \text{O}_2 (g) \rightarrow \text{N}_2\text{O}_4 (g) \quad \Delta H^0 = 11.1 \text{ kJ} \]

Calculate the \( \Delta H^0 \) for the reaction below at 25°C.

\[ 2 \text{NO}_2 (g) \rightarrow \text{N}_2\text{O}_4 (g) \]

Options:

- \(\text{+44.3 kJ}\)
- \(\text{+11.0 kJ}\)
- \(\text{-55.3 kJ}\)
- \(\text{+55.3 kJ}\)
Transcribed Image Text:Given the following at 25°C and 1.00 atm: \[ \frac{1}{2} \text{N}_2 (g) + \text{O}_2 (g) \rightarrow \text{NO}_2 (g) \quad \Delta H^0 = 33.2 \text{ kJ} \] \[ \text{N}_2 (g) + 2 \text{O}_2 (g) \rightarrow \text{N}_2\text{O}_4 (g) \quad \Delta H^0 = 11.1 \text{ kJ} \] Calculate the \( \Delta H^0 \) for the reaction below at 25°C. \[ 2 \text{NO}_2 (g) \rightarrow \text{N}_2\text{O}_4 (g) \] Options: - \(\text{+44.3 kJ}\) - \(\text{+11.0 kJ}\) - \(\text{-55.3 kJ}\) - \(\text{+55.3 kJ}\)
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