Given the data for hydrogen as it exists in nature: Isotope Atomic Mass Percent Abundance 99.985% 0.015% Hydrogen-1 1.0078 amu Hydrogen-2 2.0141 amu a) Make a prediction about the average atomic mass of hydrogen. I predict the average atomic mass of hydrogen will be the number of protons neutrons, while atomid mass (or isotopic mass) is the mass if you were to somehow weight on a balance ... To find the average atomic mass f neon, we will use the equation above and take the abundance of the inst isotope times the mass of the first isotope plus the abundance of the second isotope times the mass of the second isotope plus the abundance of the third isotope times the mans of the third isotope However, you might recall from your math courses that when y use a percentage in a calculation you always want to use the decimal form, meaning you must first divide the percentage by 100. The equation would then look (0.9048 x 19.9924 amu)-(00027 x 20.9038 amu)(0.0925x21.9914 amu) 18.009 amu -20.15 amu This is the average atomic mass of neon. Let's just take a second and see if 20.18 amu seems like a reasonable answer, given the initial data. According t the table, most neon (over 90%) has a mass of approximately 20 amu, a tiny bit has a mass of around 21 amu, and around 9% has a mass of 22 amu Based off this we would predict that the answer would be close to 20 amu, but sightly higher which it ist b) Calculate the average atomic mass of hydrogen and show all your work. c) Check your answer with a Periodic Table. What is the average atomic mass of hydrogen? d) Was your prediction correct? Explain.
Given the data for hydrogen as it exists in nature: Isotope Atomic Mass Percent Abundance 99.985% 0.015% Hydrogen-1 1.0078 amu Hydrogen-2 2.0141 amu a) Make a prediction about the average atomic mass of hydrogen. I predict the average atomic mass of hydrogen will be the number of protons neutrons, while atomid mass (or isotopic mass) is the mass if you were to somehow weight on a balance ... To find the average atomic mass f neon, we will use the equation above and take the abundance of the inst isotope times the mass of the first isotope plus the abundance of the second isotope times the mass of the second isotope plus the abundance of the third isotope times the mans of the third isotope However, you might recall from your math courses that when y use a percentage in a calculation you always want to use the decimal form, meaning you must first divide the percentage by 100. The equation would then look (0.9048 x 19.9924 amu)-(00027 x 20.9038 amu)(0.0925x21.9914 amu) 18.009 amu -20.15 amu This is the average atomic mass of neon. Let's just take a second and see if 20.18 amu seems like a reasonable answer, given the initial data. According t the table, most neon (over 90%) has a mass of approximately 20 amu, a tiny bit has a mass of around 21 amu, and around 9% has a mass of 22 amu Based off this we would predict that the answer would be close to 20 amu, but sightly higher which it ist b) Calculate the average atomic mass of hydrogen and show all your work. c) Check your answer with a Periodic Table. What is the average atomic mass of hydrogen? d) Was your prediction correct? Explain.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Atomic Structure
The basic structure of an atom is defined as the component-level of atomic structure of an atom. Precisely speaking an atom consists of three major subatomic particles which are protons, neutrons, and electrons. Many theories have been stated for explaining the structure of an atom.
Shape of the D Orbital
Shapes of orbitals are an approximate representation of boundaries in space for finding electrons occupied in that respective orbital. D orbitals are known to have a clover leaf shape or dumbbell inside where electrons can be found.
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Avg Atomic Mass =(M1*A1)+(M2*A2)+(M3+A3)/100
Or. Using decimal abundances: Avg Atomic Mass=(M1*A1)+(M2*A2)+(M3*A3)
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