21) Vanadium has two naturally occurring isotopes, 50V with an atomic mass of 49.9472 amu and 51v with an atomic mass of 50.9440. The atomic weight of vanadium is 50.9415. The percent abundances of the vanadium isotopes are % 51v % 50V and

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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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I'm confused on how to get the atomic mass average.
It's not as straight forward as adding the two given and dividing by two is it?

The question is asking for the % abundance if that isn't clear.

21) Vanadium has two naturally occurring isotopes, 50V with an atomic mass of 49.9472 amu and 51v with an atomic
mass of 50.9440. The atomic weight of vanadium is 50.9415. The percent abundances of the vanadium isotopes are
% 51v
% 50V and
Transcribed Image Text:21) Vanadium has two naturally occurring isotopes, 50V with an atomic mass of 49.9472 amu and 51v with an atomic mass of 50.9440. The atomic weight of vanadium is 50.9415. The percent abundances of the vanadium isotopes are % 51v % 50V and
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Why does the x go from:
-0.9968x = -0.0025

To:
x= 0.0025x/0.9968

And not:
x= 0.9968/0.0025

Wouldn't the negatives simply be ignored and the x would remain with:
0.9968x and then you divide then 0.0025 without the coefficient x to get the value of x by cancelling out the 0.9968?

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