A phosphorus and oxygen containing compound is 46.2494% phosphorus and 53.751% oxygen. Determine the empirical formula of the compound PxOy X = Y =

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**Determining the Empirical Formula of a Compound Containing Phosphorus and Oxygen**

Given Data:
- Percentage of Phosphorus (P): 46.2494%
- Percentage of Oxygen (O): 53.751%

**Problem Statement:**
A compound contains phosphorus and oxygen such that the mass percentage of phosphorus is 46.2494% and the mass percentage of oxygen is 53.751%. You are required to determine the empirical formula of this compound.

**Formula Representation:**
The empirical formula of the compound could be represented as \( \text{P}_X \text{O}_Y \), where \(X\) represents the number of phosphorus atoms and \(Y\) represents the number of oxygen atoms in the simplest whole-number ratio.

**Calculation:**

Fields to input the answer:
X = [   ]
Y = [   ]

**Explanation:**
To determine the empirical formula:
1. Convert the percentage composition to grams (assuming a 100 g sample, so 46.2494 g of P and 53.751 g of O).
2. Convert these masses to moles using atomic masses (P = 30.97 g/mol, O = 16.00 g/mol).
3. Divide each of the mole values by the smallest mole value obtained.
4. Obtain a ratio and round to the nearest whole number to determine the subscripts X and Y.

By following these steps and inputting values for X and Y in the provided fields, you will obtain the empirical formula of the compound.
Transcribed Image Text:**Determining the Empirical Formula of a Compound Containing Phosphorus and Oxygen** Given Data: - Percentage of Phosphorus (P): 46.2494% - Percentage of Oxygen (O): 53.751% **Problem Statement:** A compound contains phosphorus and oxygen such that the mass percentage of phosphorus is 46.2494% and the mass percentage of oxygen is 53.751%. You are required to determine the empirical formula of this compound. **Formula Representation:** The empirical formula of the compound could be represented as \( \text{P}_X \text{O}_Y \), where \(X\) represents the number of phosphorus atoms and \(Y\) represents the number of oxygen atoms in the simplest whole-number ratio. **Calculation:** Fields to input the answer: X = [ ] Y = [ ] **Explanation:** To determine the empirical formula: 1. Convert the percentage composition to grams (assuming a 100 g sample, so 46.2494 g of P and 53.751 g of O). 2. Convert these masses to moles using atomic masses (P = 30.97 g/mol, O = 16.00 g/mol). 3. Divide each of the mole values by the smallest mole value obtained. 4. Obtain a ratio and round to the nearest whole number to determine the subscripts X and Y. By following these steps and inputting values for X and Y in the provided fields, you will obtain the empirical formula of the compound.
**Problem Statement:**

Calculate the mass percentage of iron in iron(II) oxide. Use the periodic table that is given on the Canvas homepage. Enter the answer as a percentage. Do not use the % symbol.

**Chemical Compound:**
iron(II) oxide

**Answer Input:**
[Text box for answer entry]
Transcribed Image Text:**Problem Statement:** Calculate the mass percentage of iron in iron(II) oxide. Use the periodic table that is given on the Canvas homepage. Enter the answer as a percentage. Do not use the % symbol. **Chemical Compound:** iron(II) oxide **Answer Input:** [Text box for answer entry]
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