Calculate the mass of N in 4.75 × 1023 formula units of Mg3N2

Q: A particular compound is comprised only of the elements C, H, N, and Cl. Combustion analysis of…

A: Given that: Total mass of sample = 14.30 g Mass of CO2 = 31.22 g Mass of H2O = 6.764 g Mass % of N=…

Q: What is the mass (in kg) of 6.89 x 1025 molecules of CO2?  The molar mass of CO2is 44.01 g/mol.

A:

Q: Convert 7.22 x 1021 molecules/formula units of X,Z6 into grams of the same compound. (Assume that…

A: 1 mole = 6.022×1023 [ Avogadro's number ] The mass of one mole molecules of the substance is called…

Q: Determine the molar mass of Al₂(SO₄)₃･5H₂O

A: molar mass of Al₂(SO₄)₃･5H₂O. The molar mass can be calculated, first of all. Write individual…

Q: How many moles of C4H10 contains 9.25 x 10^24 molecules of C4H10?

A: Conversion of units:-             This can be done by a methond called unit factor method orcalled…

Q: What's the percentage by mass of Cl in MgCl2 if it  is 24.6% Mg by mass?

A: Intrdouction : %age by mass of Mg = 24.6%

Q: Calculate the mass in grams of 3.07×10243.07×1024 molecules of propane. The chemical formula for…

A: Given that : The number of molecules of propane = 3.07×1024 The chemical formula for propane is…

Q: A grain of sand weighs 7.7 × 10−4 g. How many formula units of silicon dioxide, SiO2, are in one…

A: The mass of one formula unit of SiO2 = 60.08 g/mol

Q: A sample containing only carbon,hydrogen,phosphorus and oxygen is subjected to elemental analysis.…

A:

Q: Calculate the mass in milligrams of 4.15×1020 formula units of Bi(NO3)3·5H2O.

A: Given : Number of formula units of Bi(NO3)3·5H2O = 4.15 X 1020

Q: Determine the number of moles in 4.00 × 10²³ formula units of MgCl₂

A: The given compound MgCl2 is made up of one magnesium atom and two chlorine atoms. One mole of…

Q: What is the percent by mass of KClO3 in the original mixture

A:

Q: A given sample of Xenon flouride compound contains molecules of the same type XeFn where n is some…

A: Chemical formula which shows number of chemical elements and total element’s number available in…

Q: Calculate the mass percent of 0.389 g of silicon (Si) that reacts with oxygen to form 0.832 g…

A: Given that:  Si = 0.389g and SiO2 = 0.832 g…

Q: What mass (in g) of Cl atoms are there in a sample that consists of 7.8e+19 formula units of…

A: Use formulas Mole=mass÷molar mass Total molecule=mole×6×1022

Q: Naphthalene, the active ingredient in one variety of mothballs, is an organic compound that contains…

A: Given, mass of naphthalene is 20.10 mg            Mass of CO2 formed =69 mg            Mass of H2O…

Q: How many SiH4 Molecules are there in 9.81 moles of SiH4? You will need to divide your answer by…

A:

Q: Determine the number of moles in 5.31 × 10²³ formula units of BaBr₂.

A: No of formula units of BaBr2 = 5.31 × 10e23 Number of moles = ?

Q: How many chloride atoms are in 32.3 g of CaCl2?

A: Since you have posted multiple questions, we are entitled to answer the first only. Please repost…

Q: c solvent) that contains 1.00 × 1012 molecules

A: moles of CHCl3 = ( molecules / Avagadro number )  moles of CHCl3 = ( 1.00 • 10^12 ) / ( 6.022 •…

Q: calculate the number of molecules in 0.256 g of NH4Cl. (molar mass of NH4Cl = 53.492 g/mol; 1 mole =…

A: Q. Given Ammonium Chloride (NH4Cl) compoundm = 0.256 g ( given mass of Ammonium Chloride)M = 53.492…

Q: Determine the number of moles in 4.21 x 10^23 molecules of CaCl2

A: One mole of any species contains avagadro number of atoms, molecules, ions etc.

Q: What is the mass in grams of 3.63 × 10-3 mol (NH4)2HPO4?

A: Given Moles of (NH4)2HPO4 = 3.63 × 10-3  To Calculate Mass of (NH4)2HPO4

Q: Cobalt(II) chloride forms several hydrates with the general formula CoCl2 ·x H2O , where  x  is an…

A: Here we are required to number of hyrate attached to the salt.

Q: 6. Çalculate the mass (in g) of 2.3 x 1021 molecules of CO2.

A: Mole concept: The number of molecules or atoms present in the one mole of the substance is equal to…

Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.