10. Natural rubidium is composed of the isotopes 8Rb, which has an actual mass of 84.9117 amu, and °'Rb. Given that the abundance ratio of 8Rb/Rb in natural rubidium is 2.591, calculate the actual mass of rubidium-87 ( Rb). 87
10. Natural rubidium is composed of the isotopes 8Rb, which has an actual mass of 84.9117 amu, and °'Rb. Given that the abundance ratio of 8Rb/Rb in natural rubidium is 2.591, calculate the actual mass of rubidium-87 ( Rb). 87
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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
Transcribed Image Text:10. Natural rubidium is composed of the isotopes 8Rb, which has an actual mass of 84.9117
amu, and °'Rb. Given that the abundance ratio of 85Rb/87Rb in natural rubidium is 2.591,
calculate the actual mass of rubidium-87 (8'Rb).
87
The average mass of rubidium from the Periodic Table is 85.468 amu
85.468 amu = A¡(84.9117 amu) + A2(X amu)
Combine the following two expressions to obtain the abundance of each isotope:
A¡/A2 = 2.591
->
A1 + A2 = 1
%3D
X = 86.909 amu
%3D
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