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- A study of patients with stage 1 breast cancer is run to assess time to progression to stage II over an observation period of 15 years. Of interest is whether there is a difference in time to progression between patients on two different chemotherapy regimens. Times to progression are measured in years from the time at which the chemotherapy regimen was initiated. (using Excel and show the table) A) Estimate the survival functions (times to progression) for each chemotherapy regimen using the Kaplan-Meier approach. B) Sketch the two survival functions above. C) Test whether there is a significant difference in time to progression between treatment regimens using the log-rank test and a 5% level of significance. D) Compute and interpret the hazard ratio for progression to stage II with the regimen I as compared to regimen 2. Years to progression by chemotherapy regimen Regimen 11 Progression No progression 12 14 13 11 15 10 8 2 6 7 3 4 6 12 Regimen 2 Progression No progression 9 11 4 14…Ims.tu.edu.sa قائمة القراءة. Remaining Time: 34 minutes, 24 seconds. v Question Completion Status: QUESTION 1 "Suppose X has an exponential distribution with ß=1/2 , then P (X2 2) is " 0.3988 O 0.0183 0.4786 O 0.2916 QUESTION 2 "Suppose X has an exponential distribution with ß=1/4 , then P (Xs1.) is " O 0.9817 O 0.3246 O 0.4105 O 0.5116 QUESTION 3One tree in the study had a weight that exceeded its expected weight (according to the best fit curve) by more than that of any other tree. By how many tons did the trees actual weight exceed the expected weight for its height?
- Q. 11 Explain the Merits and Demerits of CDR (Crude Death Rate).Please use the accompanying Excel data set or accompanying Text file data set when completing the following exercise. An article in Wood Science and Technology, "Creep in Chipboard, Part 3: Initial Assessment of the Influence of Moisture Content and Level of Stressing on Rate of Creep and Time to Failure" (1981, Vol. 15, pp. 125-144) studied the deflection (mm) of particleboard from stress levels of relative humidity. Assume that the two variables are related according to the simple linear regression model. The data are shown below x = Stress level (%) 54 54 61 61 68 68 75 75 75 y = Deflection (mm) 16.473 18.693 14.305 15.121 13.505 11.64 11.168 12.534 11.224 a. Calculate the least square estimates of the intercept (a) and slope (b). What is the estimate of o² (c)? b. Find the estimate of the mean deflection if the stress level can be limited to 66% (d). c. Estimate the change in the mean deflection associated with a 8% increment in stress level (e). (a) i (Round your answer to 2…The mortality rate from melanoma (skin cancer) during the 1950s was recorded for each of the 48 contiguous United States, plus Washington, D.C. (as reported by Fisher and Van Belle (1993) and found at http://www.stat.psu.edu/~lsimon/stat501wc/sp05/data/ The following is the scatterplot of the data: Mortality per 10 million 225 200 175 150 125 100- 30 35 Scatter plot 40 Latitude r=-.83 45 50 The plot shows a negative linear relationship between the latitude of the state and melanoma mortality rate. Which of the following is an appropriate interpretation of the negative relationship shown in the scatterplot above? A. O The more southern the state, the more people that died of melanoma. B. O The more southern the state, the higher the melanoma death rate. C. The more northern the state, the higher the melanoma death rate.
- Suppose that having a widow's peak was a dominant trait (W) compared to not having a widow's peak (w). In a sample size of 30 students, 15 were observed to have a widow's peak and 15 did not have a widow's peak. The expected frequency of a widow's peak is 75% chance of getting it and a 25% chance of not getting it. Perform a chi square analysis to see if the data above agrees with the predicted outcome.b) Calculate the fitness of a population with allele frequency x = 0.4. W = Give your answer rounded to 2 decimal places. Find the allele frequency, x, of a population with fitness 0.2. X =Recent results suggest that children with ADHD tend to watch more TV than children who are not diagnosed with the disorder. To examine this relationship, a researcher obtains a random sample of n = 36 children, 8 to 12 years old, who have been diagnosed with ADHD. Each child is asked to keep a journal recording how much time each day is spent watching TV. The average daily time for the sample is M = 4.9 hours. It is known that the average time for the general population of 8 to 12-year-old children is = 4.1 hours with = 1.8. (Hint: Be sure to use the correct test statistic). Are the data sufficient to conclude that children with ADHD watch significantly more TV than children without the disorder? Use a two-tailed test with = .05. (Be sure to give your conclusion, too) If the researcher had used a sample of n = 9 children and obtained the same sample mean, would the results be sufficient to reject H0? (Be sure to give your conclusion, too) Compute Cohen's d for this study. What is…