Given the data below about the Axial Strain (%) vs Deviator Stress: Axial Strain (%), X Deviator Stress (kPa), y 0 0 1 2 3 27.227 44.92 59.776 What is the equation form Using Lagrange Interpolation? oy=13.6135(x)(x-2)(x-3) - 22.46(x)(x-1)(x- 3) +9.96267(x)(x-1)(x-2) oy = 13.6135(x-1)(x-2)(x-3) - 22.46(x)(x-1) (x-3) + 9.96267(x)(x-1)(x-2) oy = 13.6135(x)(x-2)(x-3) + 22.46(x)(x-1)(x- 3)-9.96267(x)(x-1)(x-2) oy=13.6135(x-1)(x-2)(x-3) + 22.46(x)(x-1) (x-3)-9.96267(x)(x-1)(x-2)

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Laws of Equilibrium

A body is said to be in equilibrium if the system of forces acting on the body tends to keep the body at rest, in other words, there is no translation motion or net torque on the body. Under such conditions, the equilibrium conditions are to be applied to analyze the condition. The branch of mechanics that deals with this condition is known as 'statics'. Under equilibrium, there are no net forces on the body.