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* Next Px ? |(-50.6867-37.59+ 103.368 2)× (.37+li65p t1.lk)

* Next Px ? |(-50.6867-37.59+ 103.368 2)× (.37+li65p t1.lk)

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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10:49 PM Sun Feb 6 全40% < 88 Q engineeringpaper (1) - •.. engineeringpaper (1) EGG 211-700 T HelveticaNeue 24 O 95t - 1207 + 7S û N | -145,6867 - 82.5T + 23.3683 R 82.5J -50.686 Î - 37.59+ 103.368 ū r) * Next Px ? (- So.6867- 37.59+ 103.36る 50.6867 -37.59+ 103.3682)x(.37 tli65p thik) Solution: M= 212î + 190 j + 34.9 k N m lili
Transcribed Image Text:10:49 PM Sun Feb 6 全40% < 88 Q engineeringpaper (1) - •.. engineeringpaper (1) EGG 211-700 T HelveticaNeue 24 O 95t - 1207 + 7S û N | -145,6867 - 82.5T + 23.3683 R 82.5J -50.686 Î - 37.59+ 103.368 ū r) * Next Px ? (- So.6867- 37.59+ 103.36る 50.6867 -37.59+ 103.3682)x(.37 tli65p thik) Solution: M= 212î + 190 j + 34.9 k N m lili
10:49 PM Sun Feb 6 全40% < 88 Q engineeringpaper (1) - •.. engineeringpaper (1) EGG 211-700 HelveticaNeue 24 O February 7, 2022 Assignment Week 3 Alfonso Serna Problem 1: Find the moment about point O. Moment of Force: F, F1 = 95 i- 120 j +75 k N F2 = 165 N, a = 152°, ß = 60°, y = 80.1° X1 = 1.3 m, Y1 = 1.65 m, Z1 = 1.1 m F = 9S;- 120j+as k N 1.3i+1.65; + LIK =ノ 165(cosait cosp Ì + cos y k) (65 ( cos IS2°it cos 60°î t cos 80.1k) CoS 165 ( - 0.8829 + 0.Sĵ t 0.171929 Kl I65(-0.88297) +l65(05;) +i65(0.1719) F2 145.68635? + 82.5Î t 28.3683 K - * Next F,+ F2 95€-1207 + 7S û N -145,6867 82 SJ * + 28,3683 ñ -50.686 î - 37.5ît 103.368 K 37,5 li
Transcribed Image Text:10:49 PM Sun Feb 6 全40% < 88 Q engineeringpaper (1) - •.. engineeringpaper (1) EGG 211-700 HelveticaNeue 24 O February 7, 2022 Assignment Week 3 Alfonso Serna Problem 1: Find the moment about point O. Moment of Force: F, F1 = 95 i- 120 j +75 k N F2 = 165 N, a = 152°, ß = 60°, y = 80.1° X1 = 1.3 m, Y1 = 1.65 m, Z1 = 1.1 m F = 9S;- 120j+as k N 1.3i+1.65; + LIK =ノ 165(cosait cosp Ì + cos y k) (65 ( cos IS2°it cos 60°î t cos 80.1k) CoS 165 ( - 0.8829 + 0.Sĵ t 0.171929 Kl I65(-0.88297) +l65(05;) +i65(0.1719) F2 145.68635? + 82.5Î t 28.3683 K - * Next F,+ F2 95€-1207 + 7S û N -145,6867 82 SJ * + 28,3683 ñ -50.686 î - 37.5ît 103.368 K 37,5 li
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