Given the atmospheric state of air P=100 kPa T=45 degree Cesius Water vapor, e 5 kPa Relative Humidity is the ratio of the actual amount of water vapor in the air compared to the equilibrium amount at a specified temperature. Find the relative humidity. RH=e/es 49.4% Ob. 45.0% 56.2% O d. 68.1% Given the atmospheric state of air P=100 kPa T=45 degree Cesius Water vapor, e 5 kPa Dew-point temperature is the temperature to which the air must be cooled in order to become saturated at constant pressure. Find the dew-point temperature (degree Celsius). Find eq. at page 26 of Lec 4. О а. 25 O b. 32 Ос. 29 O d. 18 Given the atmospheric state of air P=100 kPa T=45 degree Cesius Water vapor, e = 5 kPa Find the lifting condensation level, LCL O a. 1,433 m оБ. 1,625 m O C. 2,103 m O d. 1,920 m

Given the atmospheric state of air P=100 kPa T=45 degree Cesius Water vapor, e 5 kPa Relative Humidity is the ratio of the actual amount of water vapor in the air compared to the equilibrium amount at a specified temperature. Find the relative humidity. RH=e/es 49.4% Ob. 45.0% 56.2% O d. 68.1% Given the atmospheric state of air P=100 kPa T=45 degree Cesius Water vapor, e 5 kPa Dew-point temperature is the temperature to which the air must be cooled in order to become saturated at constant pressure. Find the dew-point temperature (degree Celsius). Find eq. at page 26 of Lec 4. О а. 25 O b. 32 Ос. 29 O d. 18 Given the atmospheric state of air P=100 kPa T=45 degree Cesius Water vapor, e = 5 kPa Find the lifting condensation level, LCL O a. 1,433 m оБ. 1,625 m O C. 2,103 m O d. 1,920 m

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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