**Genetics Problem: Calculating Progeny Genotype Frequency**Given that the recombination frequency between the Q and R loci above is 32%, how many progeny with the genotype QqRr would you expect out of 100 progeny from a test cross with an individual with the genotype QqRr?- ○ 34- ○ 8- ○ 16- ○ 32- ○ 34- ○ 68**Explanation:**This question addresses the concept of recombination frequency in genetics. A recombination frequency of 32% suggests that 32% of the offspring will show recombinant phenotypes. In a typical test cross, this frequency helps determine how traits are assorted in the progeny. The result is often used to create genetic maps showing loci distance.

Name: **Genetics Problem: Calculating Progeny Genotype Frequency**Given tha
Uploaded: 2024-03-20T06:43:04.000Z
Channel: Bartleby
Description: **Genetics Problem: Calculating Progeny Genotype Frequency**Given that the recombination frequency between the Q and R loci above is 32%, how many progeny with the genotype QqRr would you expect out of 100 progeny from a test cross with an individua

ANSWER;- 16Explain;- Here we have two parents, one is a true-breeding having dominant characteristics for both the traits with genotype QQRR and the other is a true-breeding having recessive characteristics for both the traits with genotype qqrr. When we make a cross between both the parents we get all the offspring of the F1 generation having dominant characteristics for both the traits and are heterozygous with genotype QqRr. Cross between QQRR * qqrr qr qr qr qr QR QqRr QqRr QqRr QqRr QR QqRr QqRr QqRr QqRr QR QqRr QqRr QqRr QqRr QR QqRr QqRr QqRr QqRr When we make a test cross between the offspring of the f1 generation with the true-breeding recessive parent having genotype qqrr, then in the F2 generation we get the following offspring with characteristics- Cross between QqRr * qqrr qr qr qr qr QR QqRr QqRr QqRr QqRr Qr Qqrr Qqrr Qqrr Qqrr qR qqRr qqRr qqRr qqRr qr qqrr qqrr qqrr qqrr We get the ratio of offspring having genotype - QqRr : Qqrr : qqRr : qqrr = 1 :1 :1 :1. Here the parents have genotype - QqRr and qqrr, Recombinants have genotype- Qqrr and qqrr. Here we have a total of 100 offspring, and the recombination frequency between the loci Q and R is 32 %. According to formula - Recombination frequency or % recombination = total number of recombinants / total population * 100 % Here the recombination frequency = 32 % Total population = 100 But here we can observe that the offspring having genotype Qqrr is 25 %, or frequency is 0.25 Thus total number of recombinants offspring having genotype Qqrr = 32 * 0.25 = 8 Thus the total number of recombinants offspring having genotype qqRr = 32 * 0.25 = 8 So total number of recombinants = 8 + 8 = 16 Total non-recombinants or parentals = 100 - 16 = 84 Out of which parents having genotype QqRr = 42, and parents having genotype qqrr = 42 Thus the correct answer is (B) 16.