Given that the molar enthalpy of combustion of propanoic acid is -1527.2 kJ/mol, when the enthalpy change is written as a termi the chemical reaction, the reactions would be Select one: O 2C₂H5COOH(1) + 70₂(9) 6H₂O(g) + 6CO₂(g) - 1527.2 kJ O 2C₂H5COOH(1) + 70₂(g) 6H₂O(g) + 6CO₂(g) + 3054.4 kJ O 2C₂H5COOH(1) + 70₂(g) - 6H₂O(g) + 6CO₂(g) + 1527.2 kJ O 2C₂H5COOH(1) + 70₂(g) 6H₂O(g) + 6CO₂(g) - 3054.4 kJ

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Given that the molar enthalpy of combustion of propanoic acid is -1527.2 kJ/mol, when the enthalpy change is written as a term in the chemical reaction, the reactions would be
Select one:
O 2C₂H₂COOH(1) +70₂(g) → 6H₂O(g) + 6CO₂(g) - 1527.2 kJ
O 2C₂H5COOH(1) + 70₂(g) + 6H₂O(g) + 6CO₂(g) + 3054.4 kJ
O 2C₂H5COOH(1) + 70₂(g) →
6H₂O(g) + 6CO₂(g) + 1527.2 kJ
O 2C₂H5COOH(1) + 70₂(g) → 6H₂O(g) + 6CO₂(g) - 3054.4 kJ
A two-layer catalytic converter has been designed for diesel engines in automobiles. The first layer in the catalytic converter removes some nitrogen monoxide gas from the exhaust gas and converts it to ammonia gas.
In the second layer, ammonia gas is removed as it reacts with the remaining nitrogen monoxide gas. The reactions in the two layers occur at 300°C and are represented by equations I and II.
Equation I
Equation II
2NO(g) + 3H₂(g)
4NH3(g) + 6NO(g)
catalyst
catalyst
2NH₂(g) + O₂(g)
+5N₂(g) + 6H₂O(g)
ARH° -274.4 kJ
ARH° -1815.0kJ
The molar enthalpy of reaction for NH3(g) in the reaction represented by Equation II is
Record your 5-digit answer. Include sign; do not include units.
◆
kJ/mol
Transcribed Image Text:Given that the molar enthalpy of combustion of propanoic acid is -1527.2 kJ/mol, when the enthalpy change is written as a term in the chemical reaction, the reactions would be Select one: O 2C₂H₂COOH(1) +70₂(g) → 6H₂O(g) + 6CO₂(g) - 1527.2 kJ O 2C₂H5COOH(1) + 70₂(g) + 6H₂O(g) + 6CO₂(g) + 3054.4 kJ O 2C₂H5COOH(1) + 70₂(g) → 6H₂O(g) + 6CO₂(g) + 1527.2 kJ O 2C₂H5COOH(1) + 70₂(g) → 6H₂O(g) + 6CO₂(g) - 3054.4 kJ A two-layer catalytic converter has been designed for diesel engines in automobiles. The first layer in the catalytic converter removes some nitrogen monoxide gas from the exhaust gas and converts it to ammonia gas. In the second layer, ammonia gas is removed as it reacts with the remaining nitrogen monoxide gas. The reactions in the two layers occur at 300°C and are represented by equations I and II. Equation I Equation II 2NO(g) + 3H₂(g) 4NH3(g) + 6NO(g) catalyst catalyst 2NH₂(g) + O₂(g) +5N₂(g) + 6H₂O(g) ARH° -274.4 kJ ARH° -1815.0kJ The molar enthalpy of reaction for NH3(g) in the reaction represented by Equation II is Record your 5-digit answer. Include sign; do not include units. ◆ kJ/mol
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