Benzoic acid, C7H6O2, occurs naturally in many berries. Suppose you burn 1.500 g of the compound in a combustion calorimeter and find that the temperature of the calorimeter increases from 22.50 °C to 31.69 °C. The calorimeter contains 775 g of water, and the bomb has a heat capacity of 893 J/K. How much heat is evolved per mole of benzoic acid? b) Refer to problem 11 above. The balanced equation for the combustion of benzoic acid is 2 C7H6O2 (s) + 15 O2 (g) → 14 CO2 (g) + 6 H2O (l). Calculate ∆E and ∆H for the above reaction as written. Assume the reaction occurs at 31.69°C. ---------------------------------------------------------------------------------------------------------------------- Answer: a) - 3.09 × 10^3 kJ/mol b) ∆E = - 6.18 × 10^3 kJ w = + 2.534 kJ ∆H = - 6.18 × 10^3 kJ

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a) Benzoic acid, C7H6O2, occurs naturally in many berries. Suppose you burn 1.500 g of
the compound in a combustion calorimeter and find that the temperature of the
calorimeter increases from 22.50 °C to 31.69 °C. The calorimeter contains 775 g of
water, and the bomb has a heat capacity of 893 J/K. How much heat is evolved per
mole of benzoic acid?

b) Refer to problem 11 above. The balanced equation for the combustion of benzoic
acid is

2 C7H6O2 (s) + 15 O2 (g) → 14 CO2 (g) + 6 H2O (l).

Calculate ∆E and ∆H for the above reaction as written. Assume the reaction occurs
at 31.69°C.

----------------------------------------------------------------------------------------------------------------------

Answer: a) - 3.09 × 10^3 kJ/mol b) ∆E = - 6.18 × 10^3 kJ w = + 2.534 kJ ∆H = - 6.18 × 10^3 kJ

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