11. An "ice calorimeter" can be used to determine the specific heat capacity of a metal. Suppose you heat a 50.0 gram piece of an unknown metal to 99.8 °C and then drop it onto ice. When the metal's temperature has dropped to 0.0 °C, it is found that 3.54 grams of ice had melted. What is the specific heat capacity of the metal? Assume no heat lost to the surroundings: Heat released by metal = Heat absorbed by ICE %3D Heat absorbed by ICE = mAHfus ; Heat released by metal = -mcAT qice + qmetal = 0 = (3.54 g)(333 J/g)+ (50.0 g)(Cmetal)(0.0°C – 99.8°C) %3D %3D 0 = 1178.82 J- (4990 g °C)cmetal > Cmetal = 0.236 J/(g °C) %3D
11. An "ice calorimeter" can be used to determine the specific heat capacity of a metal. Suppose you heat a 50.0 gram piece of an unknown metal to 99.8 °C and then drop it onto ice. When the metal's temperature has dropped to 0.0 °C, it is found that 3.54 grams of ice had melted. What is the specific heat capacity of the metal? Assume no heat lost to the surroundings: Heat released by metal = Heat absorbed by ICE %3D Heat absorbed by ICE = mAHfus ; Heat released by metal = -mcAT qice + qmetal = 0 = (3.54 g)(333 J/g)+ (50.0 g)(Cmetal)(0.0°C – 99.8°C) %3D %3D 0 = 1178.82 J- (4990 g °C)cmetal > Cmetal = 0.236 J/(g °C) %3D
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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