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11. An "ice calorimeter" can be used to determine the specific heat capacity of a metal. Suppose you heat a 50.0 gram piece of an unknown metal to 99.8 °C and then drop it onto ice. When the metal's temperature has dropped to 0.0 °C, it is found that 3.54 grams of ice had melted. What is the specific heat capacity of the metal? Assume no heat lost to the surroundings: Heat released by metal = Heat absorbed by ICE %3D Heat absorbed by ICE = mAHfus ; Heat released by metal = -mcAT qice + qmetal = 0 = (3.54 g)(333 J/g)+ (50.0 g)(Cmetal)(0.0°C – 99.8°C) %3D %3D 0 = 1178.82 J- (4990 g °C)cmetal > Cmetal = 0.236 J/(g °C) %3D

11. An "ice calorimeter" can be used to determine the specific heat capacity of a metal. Suppose you heat a 50.0 gram piece of an unknown metal to 99.8 °C and then drop it onto ice. When the metal's temperature has dropped to 0.0 °C, it is found that 3.54 grams of ice had melted. What is the specific heat capacity of the metal? Assume no heat lost to the surroundings: Heat released by metal = Heat absorbed by ICE %3D Heat absorbed by ICE = mAHfus ; Heat released by metal = -mcAT qice + qmetal = 0 = (3.54 g)(333 J/g)+ (50.0 g)(Cmetal)(0.0°C – 99.8°C) %3D %3D 0 = 1178.82 J- (4990 g °C)cmetal > Cmetal = 0.236 J/(g °C) %3D

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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For the part circled in pencil, where did this number come from? For the part circled in yellow, what is this equation referred to as or representative of? 

11. An "ice calorimeter" can be used to determine the specific heat capacity of a metal. Suppose you heat a 50.0 gram piece of an unknown metal to 99.8 °C and then drop it onto ice. When the metal's temperature has dropped to 0.0 °C, it is found that 3.54 grams of ice had melted. What is the specific heat capacity of the metal? Assume no heat lost to the surroundings: Heat released by metal = Heat absorbed by ICE %3D Heat absorbed by ICE = mAHfus ; Heat released by metal = -mcAT 6. qice + qmetal = 0 = (3.54 g)(333 J/g) + (50.0 g)(Cmetal)(0.0°C – 99.8°C) %3D %3D 0 = 1178.82 J – (4990 g °C)Cmetal → Cmetal = 0.236 J/(g °C)
Transcribed Image Text:11. An "ice calorimeter" can be used to determine the specific heat capacity of a metal. Suppose you heat a 50.0 gram piece of an unknown metal to 99.8 °C and then drop it onto ice. When the metal's temperature has dropped to 0.0 °C, it is found that 3.54 grams of ice had melted. What is the specific heat capacity of the metal? Assume no heat lost to the surroundings: Heat released by metal = Heat absorbed by ICE %3D Heat absorbed by ICE = mAHfus ; Heat released by metal = -mcAT 6. qice + qmetal = 0 = (3.54 g)(333 J/g) + (50.0 g)(Cmetal)(0.0°C – 99.8°C) %3D %3D 0 = 1178.82 J – (4990 g °C)Cmetal → Cmetal = 0.236 J/(g °C)
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