Answered: Given that R1 = 2.40 Ω, R2 = 5.10 Ω,…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Given that R₁ = 2.40 Ω, R₂ = 5.10 Ω, R₃ = 1.80 Ω, R₄ = 3.50 Ω, R₅ = 3.60 Ω. (b) Find the equivalent resistance of the combination of R₃ and R_2,4(c) Find the equivalent resistance between points a and b. (d) If a potential difference of 6.0 V is applied across a and b, what is the current through R₁?

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Step 1

(b) The equivalent resistance of the combination of R₃ and R_2,4

$R_{2} and R_{4} are in series$

_{$\begin{array}{rcl} R_{24} & = & R_{2} + R_{4} \\ = & (5.10 Ω) + (3.50 Ω) \\ = & 8.60 Ω \end{array}$}

$R_{24} and R_{3} are in parallel$

_{$\begin{array}{rcl} R_{234} & = & \frac{R_{24} R_{3}}{R_{24} + R_{3}} \\ = & \frac{(8.60 Ω) (1.80 Ω)}{(8.60 Ω) + (1.80 Ω)} \\ = & 1.488 Ω \end{array}$}

Therefore, the equivalent resistance of the combination of R3 and R2,4 is $\begin{array}{rcl} 1 \end{array} \begin{array}{rcl} . \end{array} \begin{array}{rcl} 488 \end{array} \begin{array}{rcl} \end{array} \begin{array}{rcl} Ω \end{array}$

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