A circuit made up of 6 resistors is shown in the figure, with resistances R1 = 11 N, R2 = 65 Q, R3 = 38 Q, R4 = 69 N, R5 = 85 Q, and R6= 45 Q. The total current going through the circuit is I= 18 A. R, R4. a R3 R R, Re b Calculate the value of AV, in volts.

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A circuit made up of 6 resistors is shown in the figure, with resistances \( R_1 = 11 \, \Omega \), \( R_2 = 65 \, \Omega \), \( R_3 = 38 \, \Omega \), \( R_4 = 69 \, \Omega \), \( R_5 = 85 \, \Omega \), and \( R_6 = 45 \, \Omega \). The total current going through the circuit is \( I = 18 \, A \).

**Diagram Explanation:**

- The circuit consists of a combination of series and parallel resistors.
- Resistors \( R_1 \) and \( R_2 \) are in series, connected between points \( a \) and \( b \).
- Resistors \( R_3 \), \( R_4 \), \( R_5 \), and \( R_6 \) form a bridge or ladder-like pattern between the series segments.
- \( R_3 \) and \( R_6 \) are in parallel, and are then in series with the combination of \( R_4 \) and \( R_5 \), which are also in parallel.

Calculate the value of \( \Delta V \), in volts.
Transcribed Image Text:A circuit made up of 6 resistors is shown in the figure, with resistances \( R_1 = 11 \, \Omega \), \( R_2 = 65 \, \Omega \), \( R_3 = 38 \, \Omega \), \( R_4 = 69 \, \Omega \), \( R_5 = 85 \, \Omega \), and \( R_6 = 45 \, \Omega \). The total current going through the circuit is \( I = 18 \, A \). **Diagram Explanation:** - The circuit consists of a combination of series and parallel resistors. - Resistors \( R_1 \) and \( R_2 \) are in series, connected between points \( a \) and \( b \). - Resistors \( R_3 \), \( R_4 \), \( R_5 \), and \( R_6 \) form a bridge or ladder-like pattern between the series segments. - \( R_3 \) and \( R_6 \) are in parallel, and are then in series with the combination of \( R_4 \) and \( R_5 \), which are also in parallel. Calculate the value of \( \Delta V \), in volts.
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Step 1 (equivalent resistance)

Advanced Physics homework question answer, step 1, image 1This problem is from Network analysis (Electronics). Let's solve this problem by solving series and parallel combination of resistors to equivalent resistance and Ohm's law. Please have a good look.

 

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