A 0.140 g sample of an unknown enzyme is dissolved in water to make 0.103 L of solution. The osmotic pressure of thesolution at 25 °C is found to be 0.779 mbar. Calculate the molecular mass of the enzyme.STRATEGY1. Determine the molarity of the enzyme solution.2. Determine the moles of enzyme.3. Calculate the molecular mass of the enzyme.The molarity of the solution can be determined based on the osmotic pressure.* = R.T M(where R 0.08314 L bar K- mol-)1 bar(0.779 mbar)1000 mbarM =RT= 3.14 x 10-5 mol · L-'%3D(0.08314 L bar K-. mol-) (298 K)The moles of enzyme in 0.103 L of a 3.14 x 10- M solution is3.14 x 10-5 molx 0.103 L = 3.24 x 10-0 mol1LGiven that 0.140 g of enzyme was dissolved, what is the molecular mass of the unknown enzyme?molecular mass:g/molQuestion Source: MRG - General ChemistryMacBook Ai000D00F4F6F7F8F9F10F11%246789

GIVEN: Mass of the enzyme = 0.140 g Moles of the enzyme =3.24 x 10-6 To Calculate: Molecular mass of…

Answered: Given that 0.140 g of enzyme was…

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Given that 0.140 g of enzyme was dissolved, what is the molecular mass of the unknown enzyme? molecular mass: g/mol

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".

Question

A 0.140 g sample of an unknown enzyme is dissolved in water to make 0.103 L of solution. The osmotic pressure of the
solution at 25 °C is found to be 0.779 mbar. Calculate the molecular mass of the enzyme.
STRATEGY
1. Determine the molarity of the enzyme solution.
2. Determine the moles of enzyme.
3. Calculate the molecular mass of the enzyme.
The molarity of the solution can be determined based on the osmotic pressure.
* = R.T M
(where R 0.08314 L bar K- mol-)
1 bar
(0.779 mbar)
1000 mbar
M =
RT
= 3.14 x 10-5 mol · L-'
%3D
(0.08314 L bar K-. mol-) (298 K)
The moles of enzyme in 0.103 L of a 3.14 x 10- M solution is
3.14 x 10-5 mol
x 0.103 L = 3.24 x 10-0 mol
1L
Given that 0.140 g of enzyme was dissolved, what is the molecular mass of the unknown enzyme?
molecular mass:
g/mol
Question Source: MRG - General Chemistry
MacBook Ai
000
D00
F4
F6
F7
F8
F9
F10
F11
%24
6
7
8
9

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