Given that 0.140 g of enzyme was dissolved, what is the molecular mass of the unknown enzyme? molecular mass: g/mol

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A 0.140 g sample of an unknown enzyme is dissolved in water to make 0.103 L of solution. The osmotic pressure of the
solution at 25 °C is found to be 0.779 mbar. Calculate the molecular mass of the enzyme.
STRATEGY
1. Determine the molarity of the enzyme solution.
2. Determine the moles of enzyme.
3. Calculate the molecular mass of the enzyme.
The molarity of the solution can be determined based on the osmotic pressure.
* = R.T M
(where R 0.08314 L bar K- mol-)
1 bar
(0.779 mbar)
1000 mbar
M =
RT
= 3.14 x 10-5 mol · L-'
%3D
(0.08314 L bar K-. mol-) (298 K)
The moles of enzyme in 0.103 L of a 3.14 x 10- M solution is
3.14 x 10-5 mol
x 0.103 L = 3.24 x 10-0 mol
1L
Given that 0.140 g of enzyme was dissolved, what is the molecular mass of the unknown enzyme?
molecular mass:
g/mol
Question Source: MRG - General Chemistry
MacBook Ai
000
D00
F4
F6
F7
F8
F9
F10
F11
%24
6
7
8
9
Transcribed Image Text:A 0.140 g sample of an unknown enzyme is dissolved in water to make 0.103 L of solution. The osmotic pressure of the solution at 25 °C is found to be 0.779 mbar. Calculate the molecular mass of the enzyme. STRATEGY 1. Determine the molarity of the enzyme solution. 2. Determine the moles of enzyme. 3. Calculate the molecular mass of the enzyme. The molarity of the solution can be determined based on the osmotic pressure. * = R.T M (where R 0.08314 L bar K- mol-) 1 bar (0.779 mbar) 1000 mbar M = RT = 3.14 x 10-5 mol · L-' %3D (0.08314 L bar K-. mol-) (298 K) The moles of enzyme in 0.103 L of a 3.14 x 10- M solution is 3.14 x 10-5 mol x 0.103 L = 3.24 x 10-0 mol 1L Given that 0.140 g of enzyme was dissolved, what is the molecular mass of the unknown enzyme? molecular mass: g/mol Question Source: MRG - General Chemistry MacBook Ai 000 D00 F4 F6 F7 F8 F9 F10 F11 %24 6 7 8 9
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