The concentration of glucose in an aqueous solution can be determined by oxidation with ferricyanide ion, Fe(CN)63–. The absorbance of the ferricyanide ion measured at 420 nm increases as the concentration of glucose increases. [Glucose], mg / mL Absorbance 0.005 0.132 0.010 0.290 0.020 0.498 0.030 0.642 0.040 0.750 Using the method of least-squares, give the equation of the best straight line through the points. Make sure that m=slope has 3 decimal places (XX.XXX) and y-intercept (b) has 2 significant figures (0.0XX). In your answer you should write in the form of y=mx+b. For instance, y = 12.316x + 0.072
The concentration of glucose in an aqueous solution can be determined by oxidation with ferricyanide ion, Fe(CN)63–. The absorbance of the ferricyanide ion measured at 420 nm increases as the concentration of glucose increases. [Glucose], mg / mL Absorbance 0.005 0.132 0.010 0.290 0.020 0.498 0.030 0.642 0.040 0.750 Using the method of least-squares, give the equation of the best straight line through the points. Make sure that m=slope has 3 decimal places (XX.XXX) and y-intercept (b) has 2 significant figures (0.0XX). In your answer you should write in the form of y=mx+b. For instance, y = 12.316x + 0.072
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The concentration of glucose in an aqueous solution can be determined by oxidation with ferricyanide ion, Fe(CN)63–. The absorbance of the ferricyanide ion measured at 420 nm increases as the concentration of glucose increases.
|
[Glucose], mg / mL |
Absorbance |
|
0.005 |
0.132 |
|
0.010 |
0.290 |
|
0.020 |
0.498 |
|
0.030 |
0.642 |
|
0.040 |
0.750 |
Using the method of least-squares, give the equation of the best straight line through the points. Make sure that m=slope has 3 decimal places (XX.XXX) and y-intercept (b) has 2 significant figures (0.0XX). In your answer you should write in the form of y=mx+b. For instance, y = 12.316x + 0.072
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