Given: S1=S2=S3= 2.8 m L1=L2=L3= 6.0 m b = 300 mm h = 400 mm t = 100 mm column = 0.3 m x 0.3 m total ultimate load = 12 kN/m f'c = 20.7 MPa fy = 275 MPa Calculate the positive moment (kN-m) at the interior span bounded by FGKJ.
Given: S1=S2=S3= 2.8 m L1=L2=L3= 6.0 m b = 300 mm h = 400 mm t = 100 mm column = 0.3 m x 0.3 m total ultimate load = 12 kN/m f'c = 20.7 MPa fy = 275 MPa Calculate the positive moment (kN-m) at the interior span bounded by FGKJ.
Architectural Drafting and Design (MindTap Course List)
7th Edition
ISBN:9781285165738
Author:Alan Jefferis, David A. Madsen, David P. Madsen
Publisher:Alan Jefferis, David A. Madsen, David P. Madsen
Chapter41: Building Codes And Commercial Design
Section: Chapter Questions
Problem 41.29Q
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Question
Given:
- S1=S2=S3= 2.8 m
- L1=L2=L3= 6.0 m
- b = 300 mm
- h = 400 mm
- t = 100 mm
- column = 0.3 m x 0.3 m
- total ultimate load = 12 kN/m
- f'c = 20.7 MPa
- fy = 275 MPa
Calculate the positive moment (kN-m) at the interior span bounded by FGKJ.
![TS
S2
A
E
M
L1
B
F
LN
L2
G
K
L3
D
H
r
P](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F42615829-b6c7-48ec-89df-b9b1bebc2dae%2F9d97c31e-ac2b-4a42-a0c7-d2431fff420d%2Fnqzatnf_processed.png&w=3840&q=75)
Transcribed Image Text:TS
S2
A
E
M
L1
B
F
LN
L2
G
K
L3
D
H
r
P
![b
4](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F42615829-b6c7-48ec-89df-b9b1bebc2dae%2F9d97c31e-ac2b-4a42-a0c7-d2431fff420d%2Fzzqrhmv_processed.png&w=3840&q=75)
Transcribed Image Text:b
4
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