Given Pt² + (aq) + 2 e→→ Pt(s) Ag (aq)+eAg(s) 2 H*(aq) + 2 e -0.00 V Fe2+ (aq) + 2 e 8,-0.45 V If the iron-iron ion electrode were the standard for values instead of the hydrogen-hydrogen ion electrode, the standard reduction potentials (2) for the four half-reactions above, in corresponding order, would be: H₂(g) Fe(s) +1.20 V +0.80 V Select one: O a. +1.65 V, +1.25 V, +0.45 V, 0.00 V O b. -1.65 V, -1.25 V, -0.45 V, 0.00 V O C. +1.20 V, +0.80 V, +0.45 V, 0.00 V O d. -0.75 V, -0.35 V, -0.45 V, 0.00 V

Fundamentals Of Analytical Chemistry
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Chapter18: Introduction To Electrochemistry
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Problem 18.18QAP
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Given
Pt2(aq) + 2 e
Pt(s)
Ag (aq) + e → Ag(s)
2 H*(aq) + 2e →→ H₂(g)
°, = 0.00 V
Fe2+ (aq) + 2e → Fe(s)
= -0.45 V
If the iron-iron ion electrode were the standard for values instead of the hydrogen-hydrogen ion electrode, the standard reduction potentials () for the four half-reactions above, in
corresponding order, would be:
Select one:
O a.
O b.
+1.20 V
- +0.80 V
OC.
O d.
+1.65 V, +1.25 V, +0.45 V, 0.00 V
-1.65 V, -1.25 V, -0.45 V, 0.00 V
+1.20 V, +0.80 V, +0.45 V, 0.00 V
-0.75 V, -0.35 V, -0.45 V, 0.00 V
Transcribed Image Text:Given Pt2(aq) + 2 e Pt(s) Ag (aq) + e → Ag(s) 2 H*(aq) + 2e →→ H₂(g) °, = 0.00 V Fe2+ (aq) + 2e → Fe(s) = -0.45 V If the iron-iron ion electrode were the standard for values instead of the hydrogen-hydrogen ion electrode, the standard reduction potentials () for the four half-reactions above, in corresponding order, would be: Select one: O a. O b. +1.20 V - +0.80 V OC. O d. +1.65 V, +1.25 V, +0.45 V, 0.00 V -1.65 V, -1.25 V, -0.45 V, 0.00 V +1.20 V, +0.80 V, +0.45 V, 0.00 V -0.75 V, -0.35 V, -0.45 V, 0.00 V
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