Select the pair of products formed in the electrolysis of a solution of ZrCl4(aq) using inert electrodes. Assume that there are no overpotentials involved in any reactions. Standard reduction potentials are hs Cl₂(g) +2 e 2 Cl¯(aq) E° = +1.36 V O2(g) + 4 H*(aq) + 4 e → 2 H2O(I) 2 H2O(I) + 2 e → H2(g) + 2 OH (aq) E° = -0.83 V Zr4+ (aq) + 4 e H₂ and Cl₂ H₂ and O2 Zr and H₂ Zr and Cl₂ Zr and O₂ M Zr(s) E° = +1.23 V E° = -1.53 V

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Faraday Constant: F = 96,485.3 C/mol
Gas Constant: R = 8.3145 J K-1 mol-1 = 0.082057 L atm K-1 mol-1
Pressure: 1 atm = 1.01325 bar = 760 Torr
Temperature: 273.15 K = 0 °C
=
RT/F = 0.025693 V at T = 298.15 K
101325 Pa
Transcribed Image Text:Faraday Constant: F = 96,485.3 C/mol Gas Constant: R = 8.3145 J K-1 mol-1 = 0.082057 L atm K-1 mol-1 Pressure: 1 atm = 1.01325 bar = 760 Torr Temperature: 273.15 K = 0 °C = RT/F = 0.025693 V at T = 298.15 K 101325 Pa
Select the pair of products formed in the electrolysis of a solution of ZrCl4(aq) using
inert electrodes. Assume that there are no overpotentials involved in any
reactions.
Standard reduction potentials are
Cl₂(g) + 2 e 2 Cl¯(aq) E° = +1.36 V
O2(g) + 4 H*(aq) + 4 e − 2 H2O(I)
2 H2O(l) + 2 e → H2(g) + 2 OH (aq) E° = -0.83 V
Zr4+ (aq) + 4e¯ → Zr(s)
H₂ and Cl₂
H₂ and O2
Zr and H₂
Zr and Cl₂
Zr and O2
E° = +1.23 V
E° = -1.53 V
Transcribed Image Text:Select the pair of products formed in the electrolysis of a solution of ZrCl4(aq) using inert electrodes. Assume that there are no overpotentials involved in any reactions. Standard reduction potentials are Cl₂(g) + 2 e 2 Cl¯(aq) E° = +1.36 V O2(g) + 4 H*(aq) + 4 e − 2 H2O(I) 2 H2O(l) + 2 e → H2(g) + 2 OH (aq) E° = -0.83 V Zr4+ (aq) + 4e¯ → Zr(s) H₂ and Cl₂ H₂ and O2 Zr and H₂ Zr and Cl₂ Zr and O2 E° = +1.23 V E° = -1.53 V
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