Given: N=1000 I=1A μ = 1000 a = 1200 Hb The magnetic core is made up of iron with square. The total reluctance is Blank 1 AT/Wb, the reluctance in the two airgap is Blank 2 AT/Wb and the flux is Blank 3 mWb. -Part-A -Part-B 20 cm- 3 cm 10 cm- -2 mm ..

Given: N=1000 I=1A μ = 1000 a = 1200 Hb The magnetic core is made up of iron with square. The total reluctance is Blank 1 AT/Wb, the reluctance in the two airgap is Blank 2 AT/Wb and the flux is Blank 3 mWb. -Part-A -Part-B 20 cm- 3 cm 10 cm- -2 mm ..

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Related questions

Q: What will be the reluctance of a magnetic core if the mean path length for flux is 0.04 m and the…

A: We need to find out the reluctance for given details

Q: For the magnetic circuit shown in the figure, the iron core with N = 500 turns -Magnetic…

A: According to question: The cross sectional area is calculated as ∵a=πD24⇒a=π1×10-224⇒a=7.854×10-5m2…

Q: A coil that con sists of 450 windings is wound around a bakelite rin g. The mean diameter of the…

A: We are authorized to answer only 1 question at a time since you have not mentioned which question…

Q: length of 7 cm and cross section of 0.001 .and permeability of 0.01885 Wb/A.turns.m اختر أحد…

A: Effective thickness l=7 cm = 0.07 m. Cross sectional area a=0.001 m2. Magnetic permeability…

Q: In a coil with radius of 6 cm and 400 turns, there is a magnetic field leaving in a direction…

Q: 1 cm square 500 turns 20 cm 10 cm

Q: For the electromagnet of Figure-a. Find the flux density in the core.b. Sketch the magnetic flux…

A: The magnetic flux density (B) is the ratio of magnetic flux (∅) to area of cross section (A) and…

Q: A mmf is supplied by a current of 1 A through 100 turns. The magnetic unit consists of a steel core…

A: Reluctance =length premeability×area And rotal reluctance is the sum of reluctance of air gap and…

Q: False True Q1 In closed series magnetic circuit, the flux concentration in these parts will be low…

A: For part 1 question, In a closed series magnetic circuit, the flux concentration in these parts will…

Q: ten-turn solenoid has a ferromagnetic core with a relative permeability of 10,000. The length of the…

Q: Where specifically do you find the strongest field intensity in magnetic field vs distance

A: The magnetic field intensity is the magnetic force acting on a given unit when it is placed in a…

Q: For the ferromagnetic core shown in the gure below draw the magnetic circut for the core. The…

A: Note: Flux in the series circuit remain same Flux in parallel circuit changes based on reluctance…

Q: A magnetic circuit consists of silicon steel of 3000 permeability, of 0.078 m length and a…

Q: 2. A current of I = 3 [A] flows over the N = 200 winding wire as given in the figure below. The…

A: For the given coil with the specification the value of the magnetic flux in the each leg needs to be…

Q: A certain laminated steel core has a permeability of 3000. The length is 0.0507 m and…

Q: 3- A magnetic core with an air gap is shown in below Figure. The depth of the core is 3 cm, the…

A: Given lg =4 cmN=100μr =2000μo =4π×10-7

Q: Consider the magnetic circuit in Figure. Assuming that the core u= 1000µo has a uniform cross…

A: The solution is given below

Q: A ferromagnetic core is shown in Figure 1. The depth of the core (in to page) is 15cm, and the other…

Q: thank u no rush

Q: For the figure shown below, the permeability in the core is 4 x 10 Wb/A-tums-m. What is the value of…

Q: For the following magnetic circuit, the flux passing through the core is 1.32 mWb, the cross section…

A: The force acting on a wire positioned at right angles to the magnetic field is known as the magnetic…

Q: A magnetic core with an air gap is shown below. For a relative permeability is 3500, and the space…

A: Transformer question

Q: The applied MMF to a simple magnetic circuit is 350AT. It was found that the resulting magnetic…

A: Flux in core = flux density × area of core. But flux = mmf / reluctance. Substitute given values to…

Q: 11. There is 900 mA of current through a wire with 40 turns. What is the reluctance of the circuit…

Q: lculate the core area in Cm 2 required for a 1600kVA, 6600/440 V, 50Hz single phase transformer.…

A: Given data : Emf induced per turn : EN=30VFrequency f=50 HzFlux density, B=1.2 Wb/m2 emf induced in…

Q: F 5 cm - 5 cm 4 35 сm 15 cm 3 A 4 A 30 cm 500 turns 300 turns 0.1 cm 15 cm

A: As the circuit is series magnetic circuit so all reluctance will add simply.

Q: the armature mmf can be -2 reduced by reluctance of the magnetic the circuit in the region of the…

A: The explanation is as follows.

Q: property of a material which opposes the production magnetic flux in it is known

A: All material does. Not allow to pass the flux through it without any oppose

Q: W Discuss B-H curve of a ferro-magnetic material..

A: In this question we discuss B-H curve of ferromagnetic material.

Q: 2/5 1. The EMF of the battery is 1.4 V and its internal resistance is 12 n. It is conne. external…

Q: The length of a magnetic circuit in a moving iron instrument is 300mm.The coil around the soft iron…

Q: Example(6): A magnetic circuit containing an air gap is shown in Figure below. With the dimension as…

A: Given data, Ac=Ag=5 cm2=Area of core =Area of air gapg=gap=0.2 cmlc=20 cm=Length of coreN=100…

Q: magnetiec core the relative permeability for metal is 5000 have a gap is 0.5 cm and cross secation…

Q: The cross section of the core of a magnetic circuit with 100 relative permeability is 5 cm2 and the…

Q: A two-legged core is shown in figure below. The winding on the left leg of the core (N,) has 600…

A: Given that, N1=600 N2=200 i1=0.5 A i2=1 A μ=1000 We have to find total flux

Q: True or False: If the core material has a high reluctance, flux will flow freely in a magnetic…

Q: A solenoid has a magnetic reluctance of 2.2 x 10-3. It has 300 turns and a core area of 5 sq. cm.…

Q: Amagnetic field is being generated by a current of 2.0A flowing through 180 turns of wire on a core…

A: flux = MMFreluctance MMF = No. of turns * current in the coil . Given current in the coil = 2 amps…

Q: The magnetic structure in the figure below is made of silicon steel. Determine the values of IB…

A: Note: Relative permeability (μr) for silicon steel is not given . We assume μr = 2000 Given NB=…

Q: In the core of a long solenoid the magnetic flux density is 100 Tesla. The cross section of the…

A: Magnetic flux density (B) = 100 Tesla Diameter (d) = 10 cm

Q: Consider a magnetic core like that shown. The path length of the steal is 2 cm. The steal has a…

Q: For the following magnetic circuit, the flux density is 1 T and magnetic field intensity is 700…

Question

Given:
N=1000
I=1A
μ = 1000
a
μ = 1200
b
The magnetic core is made up of iron with square.
The total reluctance is Blank 1 AT/Wb, the reluctance in the two airgap is Blank 2 AT/Wb and the flux is Blank 3 mWb.
-Part-A
-Part-B
20 cm-
3 cm
10 cm-
-2 mm
..

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

Step 4

Step by step

Solved in 4 steps with 6 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.

Similar questions

For the magnetic circuit shown in the figure, the iron core with N = 500 turns -Magnetic permeability is 200. its average length is 40 cm -The diameter of the cross-sectional area is 1 cm. Find the current that must pass through the winding to produce 0.5 mWb of flux in a 1mm air-gap magnetic circuit?
Consider a coil as Figure 10 turns, placed in a magnetic field B= (100 x2 cos 103t) az T and R=10000 Determine the current in the circuit. The units of length are in m R -0.1 + Vemf 0.1 -0.1 B 0.1
8-9 only
A flux of 0.0016 Wb flows in a silicon sheet steel coil/core. The arrangement appears as shown below with the following dimensions: Ac = 0.0025 m? Core/gap area: Flux path length: le = 0.350 m lg = 0.0015 m N = 500 Air gap length: Number of turns: %3D A. What is the current, I, through the winding? B. What is the energy stored in the inductance? C. Assume that the current is given by i =9.75 sin (3147) A. What is the RMS voltage that would appear across the winding? D. Assume that the gap is removed from the arrangement with the flux path remaining at 0.350 m. For a flux of 0.0016 Wb, what is the inductance of the arrangement? E. What is the energy stored in the inductance with the gap removed?
hi tutor plz solve this problem with detailed explanation.
An iron circuit with a small 0.75 mm air gap is shown in Figure 1. A 6000 turn coil carries a current I = 18 mA which sets up a flux within the iron and across the air gap. The cross section of the iron is a consistent 0.8 cm?, and the mean length of the flux path is 0.15 m. a) Redraw the magnetic circuit using schematic symbols of an electric circuit with reluctance in each part of the circuit. b) State's Ohm's Law for magnetic circuit. c) By neglecting the effect of fringing, calculate the reluctance of the circuit. d) Find the flux within the core. N = 6000 Iron circuit (4, = 800 for iron). Figure 1
An iron core has a cross-sectional area of 10-3 square meter and mean circumference of 1 meter. The relative permeability of the material is 500 and the number of turns is 200. Determine the current required to set up a flux of0.001 weber. 7.54 A b. 7.96 A c. 8.19 A d. 8.47 A a.
a. Plot the direction of flux at the main poles. b. Draw the current direction at the main poles. c. Draw the direction of flux at the auxiliary poles. d. Draw the current direction at the auxiliary poles. e. Show the direction of rotation by drawing a shape.
Ip Ep=40 V f = 60 Hz N₂= 20- N₁ = 120 Find the maximum flux om om = Find the magnitude of the induced secondary voltage Es Es = units + Is Es units If the coefficient of coupling (k)= 0.75, determine the magnitude of the induced secondary voltage Es Esk=0.75 = units
Q4) Identify the unit of flux density a. (m x m)/amp b. m x m c. Wb/(m x m) d. Wb
15. A toroidal core with a mean circumference of 100 cm and a cross sectional area of 10 cm2 is wound with 500 turns of wire. What current would be required to generate a flux of 1 mWb in the core. Assume the core has a relative permeability of 800.
Consider the magnetic circuit in Figure. Assuming that the core p= 1000µo has a uniform cross section of 4 cm-,N= 600, the flux density in the air gap. 0.2 A L= 42 cm 4= 0.1 cm 35.4 mwb 120.8 mwb 106.2 mwb Non of These 76°F Rain Type here to search DELL LATIT UDE ES510