Answered: or the magnetic circuit shown in the…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Related questions

Question

For the magnetic circuit shown in the figure, the iron core with N = 500 turns -Magnetic permeability is 200. its average length is 40 cm -The diameter of the cross-sectional area is 1 cm. Find the current that must pass through the winding to produce 0.5 mWb of flux in a 1mm air-gap magnetic circuit?

O 7.5991 A
O 5.0661 A
O 4.6439 A
O 2.9552 A
O 3.7995 A

Magnetic permeability
of iron core
Air-gap
Length
Cross-sectional area of the core
Average length
= tr
of iron core
iron

Expert Solution

Step 1

According to question:

The cross sectional area is calculated as

$∵ a = \frac{{πd}^{2}}{4} \Rightarrow a = \frac{π {(1 \times 10^{- 2})}^{2}}{4} \Rightarrow a = 7.854 \times 10^{- 5} m^{2}$

The reluctance of air gap is calculated as

$∵ S_{a g} = \frac{l_{a g}}{μ_{0} μ_{r} a} \Rightarrow S_{a g} = \frac{1 \times 10^{- 3}}{4 π \times 10^{- 7} \times 1 \times 7.854 \times 10^{- 5}} \Rightarrow S_{a g} = 1 \times 10^{7} At / Wb$