Given: diameter of pipe in point 1 = 3.9in diameter of pipe in point 2 = 2.5in specific gravity of the liquid = 0.79 h(ft) = 0.60ft pressure at point 1 = 14.6 psia pressure at point 2 = 49 psia pump and motor efficiency = 66% diameter of pipe in point 4 = 4.5in diameter of pipe in point 5 = 2.3 in Z3 = 35ft With the schematic diagram of a pump, tanks, and piping determine the following: 1) The velocity of the liquid at point 2 (ft/s) 2) Pump work used by the liquid (Wpump U) (hp)
Given: diameter of pipe in point 1 = 3.9in diameter of pipe in point 2 = 2.5in specific gravity of the liquid = 0.79 h(ft) = 0.60ft pressure at point 1 = 14.6 psia pressure at point 2 = 49 psia pump and motor efficiency = 66% diameter of pipe in point 4 = 4.5in diameter of pipe in point 5 = 2.3 in Z3 = 35ft With the schematic diagram of a pump, tanks, and piping determine the following: 1) The velocity of the liquid at point 2 (ft/s) 2) Pump work used by the liquid (Wpump U) (hp)
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Given:
diameter of pipe in point 1 = 3.9in
diameter of pipe in point 2 = 2.5in
specific gravity of the liquid = 0.79
h(ft) = 0.60ft
pressure at point 1 = 14.6 psia
pressure at point 2 = 49 psia
pump and motor efficiency = 66%
diameter of pipe in point 4 = 4.5in
diameter of pipe in point 5 = 2.3 in
Z3 = 35ft
With the schematic diagram of a pump, tanks, and piping determine the following:
1) The velocity of the liquid at point 2 (ft/s)
2) Pump work used by the liquid (Wpump U) (hp)
3) Electric motor power in out (kW)
4) In figure 3, the shaded (pink) in the U tube is mercury; determine y. specific gravity of mercury 13.7
5) Mass flow rate

Transcribed Image Text:Figure 1
3
Pressurized tank
Z3
pump
2
Different diameters
See figure 3
See figure 2
5
motor

Transcribed Image Text:At point 2
Figure 2
h
Stagnation
point
At points 4 and 5
Figure 3
D5
D4
y
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