Given data of area with irregular boundary, complete the table and determine the area by trapezoidal method. (0,0) is station A.StationABсDEFGHArea5.0, 34.70.0, 20.20.0, 0.0interval10.0, 27.3offset15.0, 35.0unit/ssq. units25.0, 25.020.0, 15.035.0, 16.030.0, 5.0* Express all values up to 3 decimal places but if the value is zero just input 0.** In writing the answer/s:- do not include the unit.40.0, 20.240.0, 0.0- if the value is positive, do not include the sign- if the value is negative, include the sign without space, ex: value: - 33.000, input: -33.000

To find the area by completing the table by trapezoidal method

Given data of area with irregular boundary, complete the table and determine the area by trapezoidal method. (0,0) is station A. Station A B с D E F G H Area 5.0, 34.7 0.0, 20.2 0.0, 0.0 intervall 10.0, 27.3 offset 15.0, 35.0 25.0, 25.0 35.0, 16.0 A 20.0, 15.0 30.0, 5.0 unit/s sq. units 40.0, 20.2 40.0, 0.0 * Express all values up to 3 decimal places but if the value is zero just input 0. ** In writing the answer/s: - do not include the unit. - if the value is positive, do not include the sign - if the value is negative, include the sign without space, ex: value: - 33.000, input: -33.000

Given data of area with irregular boundary, complete the table and determine the area by trapezoidal method. (0,0) is station A. Station A B с D E F G H Area 5.0, 34.7 0.0, 20.2 0.0, 0.0 intervall 10.0, 27.3 offset 15.0, 35.0 25.0, 25.0 35.0, 16.0 A 20.0, 15.0 30.0, 5.0 unit/s sq. units 40.0, 20.2 40.0, 0.0 * Express all values up to 3 decimal places but if the value is zero just input 0. ** In writing the answer/s: - do not include the unit. - if the value is positive, do not include the sign - if the value is negative, include the sign without space, ex: value: - 33.000, input: -33.000

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Following are the perpendicular offsets that were taken from a chain survey: Change (m) 30 60 90 120 150 180 210 Offset length (m) 8.76 7.89 9.43 8.44 7.54 7.35 8.75 The area enclosed by the chain line and irregular boundary by Trapezoidal rule is m2.
39 51 45 55° 53 45 31 39.995 Solve for the length of the check base BE through the Strength of Figures with line FA as the baseline. Assume sides involved are observed in both directions. Show the Strength of Figures of both the paths. Hint: Path 1 = AABF and AABE. Path 2 = AAFE and ABFE. 41.22 31.630
Find the distance of AB = S (m) and azimuth (AB) in grad between two points whose coordinates are given below. Pick the correct answer from below. PN Y(m) X(m) A 42356.25 67452.79 B 64526.63 74523.65 Oa.23270.64m and 799.1081 Ob. 23270.64 m and 80% 3454 Oc34228.64 m and 919 2984 Od. 24228..64 m and 819,9984 Oe. 24228.64 m and 819.3454
Problem 2. Calculate the area of the closed traverse or field in square meters (using coordinate method). -2 . 12 -10 8 6 2 A (4,10) D (2,2) 2 4 6 8 B (9,7) 10 C (11,2) 12 14
7-9 please give the correct answer
Direction: Given the following data on the table. Fill up the needed data. Balance the traverse by transit rule. Solve the area by DPD or DMD. Sketch the traverse. All values must be in decimal places. COMPUTED ADJUSTED DEPARTURE LIN ADJUST ADJUST DISTAN СЕ (M) AZIMUT COMPUTED ADJUSTED LATITUDE ADJUST ED AZIMUT BEARIN DPD DOUBLE E G LATITUDE DEPARTURE ED DISTAN СЕ ED AREA (from S) BEARIN H (nearest (nearest minute) minute) +NL -SL +ED -WD +NL -SL +ED -WD АВ E S 70-29 N 10-00 650.00 ВС 895.00 CD S 26-28 315.00 DE S 65-33 W EA 875.00 410.00 N 45-31 W ТОTAL LEC : RP (nearest hundred) AREA ..
it said i got 1 item wrong. im so confused now. where did i go wrong? (btw this is only a activity for us to practice but i still don't get it)
What is the area of ABED if AB is parallel to CE and BCD is a right-angled triangle at B having area 30 square metres?
Q7) Calculate the coordinates. Check whether the error is acceptable. Make corrections. N 59.0701g S2 145.5558g S1 161.51849 A x=315.122m $3 S6 120.6210g 167.8089g S4 F S5 Y (m) x (m) Дх B (grad) a (grad) S (m) Ay STATION A 137.619 214.077 170.542 D 189.664 225.219 F 156.907 A 8 y=74.056m
3. A and B are two points located on each bank of a river and near the abutments of a proposed bridge. To determine its distance, a baseline CD 180 m long was established on one bank of the river and the transit was set up at stations C and D and the azimuth were taken as follows: Azimuth LINE (degrees) 210°00' С - D C - A 260°00' 290°00' С -В D - A D - B 301°00' 315°00' 1. Find the distance AD.
x2 The asymptote of the hyperbola given by 1 has the equation 9 4 2х- Зу %3D0 Зх - 2у %3D 0 O A. В. 2х - у %3D 0 2x + y = 0 C. D.