Given data for Preparation of Methyl BenzoateMass of benzoic acid used: 5.040 gramsVolume of methanol used: 12.0 mLMass of Methyl Benzoate Obtained: 4.810 gramsplease help find the %yield and limiting regent given the data for the expirement Percent yield of methyl benzoate(show working...include compound name orabbreviation)? Working need not be shown in conclusion.For reaction A ---> B5.00 g Ax 1 mol A x 1 mol B x 181 g B = 6.65 g B136 g A 1 mol A 1 mol Bmay be expressed as.5.00 g Ax (1mol A/136 g A) x (1 mol A/1 mol B) x (181 g B/1 mol B) = 6.65 g B Determine the limiting reagent. Sulfuric acid is a catalyst, and need not to beconsidered (show working).For example...For A+B ----> C20.00 g Ax 1mol A x 1 = mole ratio AMW A 1 mol Acan be represented as.. 20.00 g Ax (1 mol A/MW A) x ( 1/1 mol A) = mol ratio A

Given: Mass of benzoic acid used = 5.040 gVolume of methanol used = 12.0 mLMass of Methyl Benzoate…

Answered: Given data for Preparation of Methyl…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Given data for Preparation of Methyl Benzoate
Mass of benzoic acid used: 5.040 grams
Volume of methanol used: 12.0 mL
Mass of Methyl Benzoate Obtained: 4.810 grams

please help find the %yield and limiting regent given the data for the expirement

Percent yield of methyl benzoate(show working...include compound name or
abbreviation)? Working need not be shown in conclusion.
For reaction A ---> B
5.00 g Ax 1 mol A x 1 mol B x 181 g B = 6.65 g B
136 g A 1 mol A 1 mol B
may be expressed as.
5.00 g Ax (1mol A/136 g A) x (1 mol A/1 mol B) x (181 g B/1 mol B) = 6.65 g B

Determine the limiting reagent. Sulfuric acid is a catalyst, and need not to be
considered (show working).
For example...For A+B ----> C
20.00 g Ax 1mol A x 1 = mole ratio A
MW A 1 mol A
can be represented as.. 20.00 g Ax (1 mol A/MW A) x ( 1/1 mol A) = mol ratio A

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