47) For each of the fallowing unbalanccel equation, by calculation which, reactant is the Limiting Suppose Oa of euch reactant is taken Show. Calculate Hthe mass of each product that is expe nt Co2 187 5ynol x44.01a Imal= 1875 mol CO Imass of HeO produced 8.25199 B. Alis)+ Clzla)> AIGl3iss naole of A-(10u 12685a/mol)=.3706mul %3D =4.5025g %3D 1410 mol mosso of AICI, produced = .094mol x133.34g/mol /2.5340g C. NaOH(s) + COz(4) → Na COgs) + H2O12) (.25 mol NaOH)x[lmol_Na,CO3/2mol NAOH)=.12S mol Na,coz muss of Na,0, prduced =125motiWS.4888glmol = 13.2486g 4,25 mot NaOH)x (I mel HzO/2ml NallH)=125mol HzO of pradlucecd E,125 mul = 2. D. NatHCO 6s) + HGlcug) → NaClyag) + Hez011) +
47) For each of the fallowing unbalanccel equation, by calculation which, reactant is the Limiting Suppose Oa of euch reactant is taken Show. Calculate Hthe mass of each product that is expe nt Co2 187 5ynol x44.01a Imal= 1875 mol CO Imass of HeO produced 8.25199 B. Alis)+ Clzla)> AIGl3iss naole of A-(10u 12685a/mol)=.3706mul %3D =4.5025g %3D 1410 mol mosso of AICI, produced = .094mol x133.34g/mol /2.5340g C. NaOH(s) + COz(4) → Na COgs) + H2O12) (.25 mol NaOH)x[lmol_Na,CO3/2mol NAOH)=.12S mol Na,coz muss of Na,0, prduced =125motiWS.4888glmol = 13.2486g 4,25 mot NaOH)x (I mel HzO/2ml NallH)=125mol HzO of pradlucecd E,125 mul = 2. D. NatHCO 6s) + HGlcug) → NaClyag) + Hez011) +
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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D
Transcribed Image Text:m) o)x4 mol H2O/5 mol 0)=.25mol Hz0
13125mol 0 2mal C0/Smol Oz.175 moñ9t
Calculate the mass of each product that is
by calculation which reuctant is the Limiting
Suppose Oa of euch reactant is taken Show
47) For
each of the
olowing unbalanced equation,
expectint.
A.C
Co2
187 5pmol x44.019lmal=8.25199)
Imass of HeO prodcuied
6. Alis)+ Clziq) > AIGlziss
=4.5025g
Nes of AICI3 produced =.094mol x133.344 Imol 12.52
C. NaOHIS) + COz(4) → Na COgs) + HzO12)
(25 mol NaOH)x[Imol Na,CO,/2mol NaOH)=.125 mol Na_Ces
muss of Na,0g produad =125meli45.49888glmol = 13.28g
4.25mot NaOH)x(1 ml HzO/2ml NalH) =.125mol HzO
of
!!
D. NatHcOs65) + HGlcag) > NaCleag) + HeOll) +
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