Given a set of N nuts of different sizes and N bolts of different sizes. There is a one-one mapping between nuts and bolts. Match nuts and bolts efficiently. Comparison of a nut to another nut or a bolt to another bolt is not allowed. It means nut can only be compared with bolt and bolt can only be compared with nut to see which one is bigger/smaller. The elements should follow the following order ! # $ % & * @^ ~.
Given a set of N nuts of different sizes and N bolts of different sizes. There is a one-one mapping between nuts and bolts. Match nuts and bolts efficiently. Comparison of a nut to another nut or a bolt to another bolt is not allowed. It means nut can only be compared with bolt and bolt can only be compared with nut to see which one is bigger/smaller. The elements should follow the following order ! # $ % & * @^ ~.
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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C++, do not sort the array.
![Given a set of N nuts of different sizes and N bolts of different
sizes. There is a one-one mapping between nuts and bolts. Match
nuts and bolts efficiently.
Comparison of a nut to another nut or a bolt to another bolt is not
allowed. It means nut can only be compared with bolt and bolt can
only be compared with nut to see which one is bigger/smaller.
The elements should follow the following order ! # $ % & * @^~.
Example 1:
Input:
N = 5
nuts[] = {@, %, $, #, ^}
{%, @, #, $ ^}
%3D
bolts[]
Output:
# $ % @
#](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7be48886-48d4-4697-92c8-bb0e1ec489cc%2Ff42a68dd-529b-4a8b-91bf-837100e94b81%2Ft7hb9to_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Given a set of N nuts of different sizes and N bolts of different
sizes. There is a one-one mapping between nuts and bolts. Match
nuts and bolts efficiently.
Comparison of a nut to another nut or a bolt to another bolt is not
allowed. It means nut can only be compared with bolt and bolt can
only be compared with nut to see which one is bigger/smaller.
The elements should follow the following order ! # $ % & * @^~.
Example 1:
Input:
N = 5
nuts[] = {@, %, $, #, ^}
{%, @, #, $ ^}
%3D
bolts[]
Output:
# $ % @
#
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