Given a plaster of paris (PoP) slab with L = 0.052 cm, W = 0.052 cm, and H = 0.0095 cm, what is the heat transfer coefficient if the biot number is 0.19682? Attached is the Heisler Chart below.Other data (if necessary):Initial Temperature: 328.2 CSurrounding Temperature: 27.9 CPoP Density: 680 kg/m^3Heat Capacity: 1090 J/kgKThermal Conductivity: 0.1185 W/mK 100 501.0200.7-100.50.40.30.20.78.30.10.3 0.5 0.8 1.00.to0.31230.29100-Bi = klhLRi-10.1니 0.07251250A3560.404570,801.0208.85N0.80.03160.60.50.40.020.010.0070.38.8850.0030.10.0020.050.00114 6 8 10121416 18202224262830405060708090 110 130 150300 400 500 600 700* = (at/L?) = FoFIGURE 5S.1 Midplane temperature as a function of time for a plane wall of thickness 2L [1]. Used with permission.

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Answered: Given a plaster of paris (PoP) slab…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

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Given a plaster of paris (PoP) slab with L = 0.052 cm, W = 0.052 cm, and H = 0.0095 cm, what is the heat transfer coefficient if the biot number is 0.19682? Attached is the Heisler Chart below.

Other data (if necessary):
Initial Temperature: 328.2 C
Surrounding Temperature: 27.9 C
PoP Density: 680 kg/m^3
Heat Capacity: 1090 J/kgK
Thermal Conductivity: 0.1185 W/mK

100 50
1.0
20
0.7
-10
0.5
0.4
0.3
0.2
0.7
8.3
0.10.3 0.5 0.8 1.0
0.
to
0.3
1
2
3
0.2
9100
-Bi = klhL
Ri-1
0.1
니 0.07
25
12
50
A35
60.
40
45
70,80
1.0
20
8.85
N0.8
0.03
16
0.6
0.5
0.4
0.02
0.01
0.007
0.3
8.885
0.003
0.1
0.002
0.05
0.001
1
4 6 8 10121416 18202224262830405060708090 110 130 150
300 400 500 600 700
* = (at/L?) = Fo
FIGURE 5S.1 Midplane temperature as a function of time for a plane wall of thickness 2L [1]. Used with permission.

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