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Given a dictionary d, return a new dictionary where all occurences of x as a value (not a key) is replaced with y. def replace_all(d, x, y): >>> d = {'foo': 2, 'bar': 3, 'garply': 3, 'xyzzy': 99} >>>e= replace_all(d, 3, 'poof') >>> e == {'foo': 2, 'bar': poof', 'garply': 'poof', 'xyzzy': 99} True HHH www "*** YOUR CODE HERE *******"

Given a dictionary d, return a new dictionary where all occurences of x as a value (not a key) is replaced with y. def replace_all(d, x, y): >>> d = {'foo': 2, 'bar': 3, 'garply': 3, 'xyzzy': 99} >>>e= replace_all(d, 3, 'poof') >>> e == {'foo': 2, 'bar': poof', 'garply': 'poof', 'xyzzy': 99} True HHH www "*** YOUR CODE HERE *******"

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Given a dictionary d, return a new dictionary where all occurences of x as a value (not a key) is replaced with y. def replace_all(d, x, y): >>> d = {'foo': 2, 'bar': 3, 'garply': 3, 'xyzzy': 99} >>> e = replace_all(d, 3, 'poof') >>> e == {'foo': 2, 'bar': poof', 'garply': 'poof', 'xyzzy': 99} True 11 '*** YOUR CODE HERE ***
Transcribed Image Text:Given a dictionary d, return a new dictionary where all occurences of x as a value (not a key) is replaced with y. def replace_all(d, x, y): >>> d = {'foo': 2, 'bar': 3, 'garply': 3, 'xyzzy': 99} >>> e = replace_all(d, 3, 'poof') >>> e == {'foo': 2, 'bar': poof', 'garply': 'poof', 'xyzzy': 99} True 11 '*** YOUR CODE HERE ***
Expert Solution
Step 1

code:-

def replace_all(d, a, b):
    result = {}
    for k in d:
        if d[k]==a:
            result[k] = b
        else:
            result[k] = d[k]
    return result

 

d = {'foo': 2, 'bar': 3, 'garply': 3, 'xyzzy': 99}

e = replace_all(d, 3, 'poof')

print(e == {'foo': 2, 'bar': 'poof', 'garply': 'poof', 'xyzzy': 99})

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