Given A= 2n + 1-2, show that for any 4, the number of ways you can have the same value of a given any value of n and l (where n = 1,2,3... and l = 0, 1,2,...) is ^²+3^-41; that is, degeneracy = ³² + 34-46
Given A= 2n + 1-2, show that for any 4, the number of ways you can have the same value of a given any value of n and l (where n = 1,2,3... and l = 0, 1,2,...) is ^²+3^-41; that is, degeneracy = ³² + 34-46
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![Given A = 2n + 1-2, show that for any 4, the number of ways
you can have the same value of A given any value of n and
1 (where n = 1, 2, 3 ... and l = 0₁1₁2,...) is ^²+3^-41; that
is,
degeneracy = 4² + 34 - 46
s](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff9ae494b-0c93-4c1c-b8b9-6bc9a50e90cb%2Ffa59feb3-9295-47e9-9d17-9a13bf87f0c6%2Frvg8lh5_processed.png&w=3840&q=75)
Transcribed Image Text:Given A = 2n + 1-2, show that for any 4, the number of ways
you can have the same value of A given any value of n and
1 (where n = 1, 2, 3 ... and l = 0₁1₁2,...) is ^²+3^-41; that
is,
degeneracy = 4² + 34 - 46
s
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