3. In this problem, you may use the following formulae without further justification: Σ k²³ = (n(n + ¹)) ². 2 k=1 k=1 n(n+1) 2 3 12 k=1 n(n+1)(2n + 1) k² 1 6 (a) Find a formula in n for each of 71 TL Σ(2k) and Σ(2k – 1). k=1 k=1 (b) Find a formula in n for each of n Σ(2k)² and (2k-1)². k=1 (c) Find a formula in n for each of TL n k=1 TL Σ(2k)³ and (2k-1)³.

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A: