Give the reaction mechanism (showing curly arrows) for the bromination of methane in the presence of ultra violet (uv) light, producing free radicals. Give at least one reaction of each.
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Give the reaction mechanism (showing curly arrows) for the bromination of methane in the presence of ultra violet (uv) light, producing free radicals. Give at least one reaction of each.
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- Alkynes do not react directly with aqueous acid as do alkenes, but will do so in the presence of mercury(II) sulfate as a Lewis acid catalyst. The reaction occurs with Markovnikov regiochemistry, so the OH group adds to the more highly substituted carbon and the H adds to the less highly substituted carbon. The initial product of the reaction is a vinyl alcohol, also called an enol. The enol immediately rearranges to a more stable ketone via tautomerization. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions -X티 Hö: H-O -CH3 -CH3 H30*You are required to synthesize 2-bromopentane from the reaction between an alkene with HBr. Which alkene, 1-pentene or 2-pentene, should you react with HBr in order to get 2-bromopentane? Give an explanation.Elimination of HBr from 2-bromobutane affords a mixture of 1-butene and 2-butene. With sodium ethoxide as base, 2-butene constitutes 81% of the alkene products, but with potassium tert-butoxide, 2-butene constitutes only 67% of the alkene products. Offer an explanation for this difference.
- Bromine reacts with alkenes in methanol according to the equation when this reaction was carried out with 4-tert-butylcyclohexene, only one isomer was formed with the molecular formula C12H23BrO (80% yield). Which of the following is the structure more reasonable for this compound? Explain your reasoning through a corresponding mechanism.Draw the organic product obtained on treatment of each of the following two alkenes with bromine: (a) trans-2-pentene and (b) 1- methylcyclohexene. Having done this, draw the product of the reaction of these same alkenes with bromine in aqueous solution.X Upon ozonolysis, Compound X produces two compounds: Compound Y and Compound Z. Compound Y can also be prepared from the following synthetic route: PCC 1. R₂BH, THF 1. Mg. Et₂O PCC Compound Y 2. CH₂Cl₂ 2. NaOH, HO CH₂Cl₂ 3. H₂O* From this information, draw the structures of Compounds X, Y, and Z. For Compounds X and Z, different substituents are possible. For grading purposes, just use hydrogens as the substituents. Br مرد →] ►
- An unknown hydrocarbon A with the formula C6H10 reacts with 1 molar equivalent of H2 over a palladium catalyst to give B C6H12 (Rxn 1). Hydrocarbon A also reacts with OsO4 to give the glycol C (Rxn 2). A gives 5-oxohexanal on ozonolysis (Rxn 3). Draw the structures of A, B, and C. Give the reactions.a) When (Z)-3-methylhex-3-ene undergoes hydroboration–oxidation, two isomeric products are formed. Give their structures, and label each asymmetric carbon atom as (R) or (S). What is the relationship between these isomers?3-Chloro-2-methylpropene reacts with sodium methoxide in methanol to form 3-methoxy-2-methylpropene. For each of the following changes in the reaction conditions, state whether the reaction rate would increase, decrease, or remain the same. Explain your reasoning. In some cases the identity of the major organic product would be expected to change; in such cases, give the expected major product. (a) the same quantities of reagents are dissolved in half the volume of methanol (b) 3-bromo-2-methylpropene is used in place of 3-chloro-2-methylpropene (c) sodium methanethiolate (CH3SNa) is used in place of of sodium methoxide
- A hydrocarbon (X), with the molecular formula: C8H14 is reduced in presence of sodium and liquid ammonia to give the only product (Y) with the molecular formula: C8H16. Compounds X and Y both resulting 2,5-dimethylhexane when treated with hydrogen and platinum catalyst (H2/Pt). As a result of the oxidative cleavage of compound Y (by using KMnO4 / H2SO4), a single carboxylic acid derivative with C4H8O2 molecular formula is formed. Again, as a result of the reaction of Y with perbenzoic acid, the chiral compound C8H14O is observed, but the reaction of compound Y with bromine gives the achiral C8H14Br2 as the product.Alkenes can be hydrated to form alcohols by (1) hydroboration followed by oxidation with alkaline hydrogen peroxide and (2) acid-catalyzed hydration. Compare the product formed from each alkene by sequence (1) with those formed from (2). Q.)1-MethylcyclohexeneTwo products are possible when pent-2-ene is treated with HBr. Write the structures of the possible products, and explain why they are made in about equal amounts.