Give the null and alternative hypothesis for a given situationCompare means of two independent groups using t-test.Using the p-value of the computed t-test to whether accept the null hypothesis or not. Instructions:Use Minitab, spss or excel to compute for the t-test of the following data.Data: Is there a significance difference in the mean scores of the students exposed tothe two methods of teaching Biostatistics? The following are the scores of the students.New MethodTraditional Method8068797178696962685278677563747073598161

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Give the null and alternative hypothesis for a given situation Compare means of two independent groups using t-test. Using the p-value of the computed t-test to whether accept the null hypothesis or not.

Give the null and alternative hypothesis for a given situation Compare means of two independent groups using t-test. Using the p-value of the computed t-test to whether accept the null hypothesis or not.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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For the situation described below, state the null hypothesis, Ho, and the alternative hypothesis, H, to be tested. (Enter != for # as needed.) A statistical test is designed to show that the proportionp of defectives has decreased below 0.6%. Ho: 0.6 H: 0.6
While an independent samples t-test compares two separate groups of people, a paired sample t-test compares the same group of people over time or across two different treatments or events or etc. True False
Imagine you are doing a Related-Samples t-test, and you are on Step Two of the hypothesis test. The sample of difference scores that you calculated is -1, -1, -3, +2, 0, -4. If you are doing the test with α = .01, and two tails, what would he correct t-critical be?
Suppose that in a random selection of 100 colored candies, 21% of them are blue. The candy company claims that the percentage of blue candies is equal to 20%. Use a 0.10 significance level to test that claim. H, p#0.2 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is (Round to two decimal places as needed.)
If the p-value is very large (say close to 1), then it is likely that we will reject the null hypothesis. True False
What values of F indicate that the null hypothesis is true?
The proportion of defective items is not allowed to be over 12%. A buyer wants to test whether the proportion of defectives in his shipment of 1000 items exceeds the allowable limit. The buyer takes a SRS of 100 items and finds that 19 are defective. State the null and alternative hypotheses for this test. Group of answer choices Ho: p = 0.12 vs Ha: p > 0.12 Ho: p = 0.19 vs Ha: p ≠ 0.12 Ho: p = 0.12 vs Ha: p < 0.19 Ho: p = 0.12 vs Ha: p = 0.19
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For the next items, identity the appropriate statistical test that will be utilized in hypothesis testing. SE T- test T- test (one factor/sample) (Dependent) (Independent) T-test F- Test (Standard Error)
A researcher wants to determine if there is a significant difference in the number of times a new treatment for a medical condition results in relief from symptoms compared to the standard treatment. They randomly assign 20 patients to receive the new treatment and 20 to receive the standard treatment, and record the number of times each patient experienced relief from symptoms in a given period of time. The researcher uses the Wilcoxon Signed-Ranks Test to analyze the data. What is the null hypothesis for this test?
Three students, an athlete, a fraternity member, and an honors student, record the number of hours they slept each night for 20 nights. O JMP Applet imp ? Oneway Analysis of Sleep Hours By Student Oneway Analysis of Sleep Hours By Student 10 Oneway Anova 14 Summary of Fit 12 Rsquare 0.024506 10- Adj Rsquare Root Mean Square Error Mean of Response Observations (or Sum Wgts) -0.00072 1.99517 7.7 60 Analysis of Variance Sum of Mean F Prob > Source DF Squares Square Ratio F 2 Athiete Frat Honors Student 2 5.70000 2.85000 0.7180 0.4931 Student Error 57 226.90000 3.98070 C. Total 59 232.60000 Oneway Anova Means for Oneway Anova Std Lower Upper 95% Summary of Fit Level Number Mean Error 95% Athlete 20 8.10000 0.44813 7.2086 8.9934 Rsquare 0.024506 Frat 20 7.65000 0.44813 6.7588 8.5434 Adj Rsquare Root Mean Square Error Mean of Response Observations (or Sum Wgts) -0.00972 Honors 20 7.35000 0.44813 6.4586 8.2434 1.99517 Std Error uses a pooled estimate of error variance 7.7 60 Analysis of…