Give the marginal probability of (d) *X = number of Bars of Signal StrengthY = response time(Nearest second)13P(Y)40.150.10.0530.020.10.0520.020.030.210.010.020.25dP(X)О озО 0.28О 0.25O None of the choices

Probability The probability of an event specifies the likelihood of its happening. For example, the…

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A First Course in Probability (10th Edition)

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Author:Sheldon Ross

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Chapter1: Combinatorial Analysis

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Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Let X = Red blood cell count in millions per cubic millimeter of whole blood for healthy females ex has been approximately normal distribution which means U = 5.1 and standard deviation O = 0.6 (a) Convert the x interval, 4.5 < x, to a z interval. (Round your answer to two decimal places.) (b) Convert the x interval, x < 4.2, to a z interval. (Round your answer to two decimal places.) (c) Convert the x interval, 4.0 < x < 5.5, to a z interval. (Round your answers to two decimal places.) (d) Convert the z interval, z < -1.44, to an x interval. (Round your answer to one decimal place.) (e) Convert the z interval, 1.28 < z, to an x interval. (Round your answer to one decimal place.) (f) Convert the z interval, -2.25 < z < -1.00, to an x interval. (Round your answers to one decimal place)
5. S Jn Show that the 95 percent fiducial limits for the mean of the population are x ± to.05, where to.05, stands for the value of t at 5 percent level of significance. Deduce that for a random sample of 16 values with mean 41.5 inches and the sum of the squares of the deviations from the mean 135 (inches)² and drawn from a normal population, 95 percent fiducial limits for the mean of the population are 39.9 and 43-1 inches.
9
Give the marginal probability of (e) * X = number of Bars of Signal Strength Y = response time (Nearest second) 1 2 3 P(Y) 4 0.15 0.1 0.05 3 0.02 0.1 0.05 2 0.02 0.03 0.2 -- 1 0.01 0.02 0.25 -- P(X) e О 02 O 0.25 О 0.55 O None of the choices
2t 2.15 A critical part has the following failure distribution: ƒ(t) · 40 OseS 40 yr. 402, 402 » Find: (a) R(1yr) (b) MTTF
How would you report the results? The derived t = 0.02 was not significant at p = .05 with df = 10. Therefore, Ho was not rejected, and it was concluded that the mean pretest score for students at the beginning of the semester (18.27) was not different than the mean posttest score for students at the end of the semester (22.00), t(10) -= 0.02, p .05. In terms of the research question, it appears that the curriculum was not effective in promoting learning.
Explain into detial and show all steps for me to understand how to do it by myself please. Thank you.
A population of values has a normal distribution with μ=14.8 and σ=6.5. You intend to draw a random sample of size n=131. Find the probability that a single randomly selected value is less than 13.P(X < 13) = Find the probability that a sample of size n=131 is randomly selected with a mean less than 13. P( ¯x < 13) = Enter your answers as numbers accurate to 4 decimal places. Answers should be obtained using z-scores correct to two decimal places.
Consider the problem of diagnosing a rare disease. Let’s say the occurrence of thisdisease is one in a thousand i.e. P(D = +) = 0.001. There is a test T which correctlyidentifies the disease 99.9% of the time, i.e. P(T = +|D = +) = 0.999. However, italso has a false positive rate of 0.02, i.e. P(T = +|D = −) = 0.02 i. If a random person from the population is tested, what is the probability they willreceive a positive test, i.e. P(T = +)? ii. Given that the test is positive, what is the probability that the person has the disease,i.e. P(D = +|T = +)?
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(1.5,2) 1.5 (0,7, 0.2) f0.7,0.2) O5 ー15 -0.5 0.5 1.5 - 0.57 (-1.2,-1) - 15 -2 what are the values Inthe losed interval (-1.2,1.5) where 'undehned? What are the crithcal valuesof f? at x = %3D Where is f's0? xin theinterval Where is f'

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Give the marginal probability of (d) * Y = response time (Nearest second) X = number of Bars of Signal Strength P(Y) 1 2 3 4 0.15 0.1 0.05 -- 3 0.02 0.1 0.05 -- 0.02 0.03 0.2 -- 1 0.01 0.02 0.25 d P(X) 0.3 O 0.28