5. Show that the 95 percent fiducial limits for the mean of the population are x± √ ¹00s, where to.os, stands for the value of t at 5 percent S Vn level of significance. Deduce that for a random sample of 16 values with mean 41.5 inches and the sum of the squares of the deviations from the mean 135 (inches)² and drawn from a normal population, 95 percent fiducial limits for the mean of the population are 39.9 and 43-1 inches.

5. Show that the 95 percent fiducial limits for the mean of the population are x± √ ¹00s, where to.os, stands for the value of t at 5 percent S Vn level of significance. Deduce that for a random sample of 16 values with mean 41.5 inches and the sum of the squares of the deviations from the mean 135 (inches)² and drawn from a normal population, 95 percent fiducial limits for the mean of the population are 39.9 and 43-1 inches.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018

18th Edition

ISBN:9780079039897

Author:Carter

Publisher:Carter

Chapter10: Statistics

Section10.4: Distributions Of Data

Problem 22PFA

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