• get_tokens_from_equation(line): Takes one string as input that contains any combination of digitsfrom 0-9 and the following mathematical symbols:+ - x / = ^ (OThe string does not have to correspond to a valid mathematical equation. For example, '4-3=0'and '4xx5=(8' could be valid inputs to this function.The function will translate the string into a list of tokens. A token is a single non-negative number(of any length) or a single mathematical symbol. Numbers should be added to the list as integers,and symbols as strings. The tokens in the list should be in the same order as the numbers/symbolsappear in the string.For example, given the string '52-2=50', the function should return the list [52, '-',50].>>> get_tokens_from_equation('4=3')[4, '=', 3]>>> get_tokens_from_equation('6-5=15^4/2')[6, '-', 5, '=', 15, '^', 4, '/', 2]>>> get_tokens_from_equation('288/24x6=18x13x8')[288, '/', 24, 'x', 6, '=', 18, 'x', 13, 'x', 8]

1) Below is program to define a function get_token_from_equation and test with line inputs It…

Answered: get tokens_from_equation(line): Takes…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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how do i make a test a function in javascript with instructions as follows allAnagrams( words ) This function accepts a single string. The string contains zero or more words, each separated by spaces. This function must return true if each of the words is an anagram of the others and return false otherwise. Examples allAnagrams("naps pans span") => true allAnagrams("") => true allAnagrams("part tarp rappt") => false allAnagrams("span span") => true allAnagrams("spear pears parse pares reaps") => true this HAS to take in one string as the input
The countSubstring function will take two strings as parameters and will return an integer that is the count of how many times the substring (the second parameter) appears in the first string without overlapping with itself. This method will be case insensitive. For example: countSubstring(“catwoman loves cats”, “cat”) would return 2 countSubstring(“aaa nice”, “aa”) would return 1 because “aa” only appears once without overlapping itself. public static int countSubstring(String s, String x) { if (s.length() == 0 || x.length() == 0) return 1; if (s.length() == 1 || x.length() == 1){ if (s.substring(0,1).equals(x.substring(0,1))){ s.replaceFirst((x), " "); return 1 + countSubstring(s.substring(1), x); } else { return 0 + countSubstring(s.substring(1), x); } } return countSubstring(s.substring(0,1), x) + countSubstring(s.substring(1), x); } public class Main { public static void main(String[] args) { System.out.println(Recursion.countSubstring("catwoman loves cats","cat"));…
Implement the following function: Code should be written in python.
Please help. This is Python I feel so lost
Write T if the sentence is right; write F else, and fix the incorrect one. You need only respond to 5 of the following questions.The get() function may be used to append a new plot to an existing one.
Ex: Use getline() to get a line of user input into a string. Output the line. Enter text: IDK if I'll go. It's my BFF's birthday. You entered: IDK if I'll go. It's my BFF's birthday. Search the string (using find()) for common abbreviations and print a list of each found abbreviation along with its decoded meaning. Ex: Enter text: IDK if I'll go. It's my BFF's birthday. You entered: IDK if I'll go. It's my BFF's birthday. BFF: best friend forever IDK: I don't know Support these abbreviations: BFF -- best friend forever IDK -- I don't know . JK -- just kidding TMI -- too much information TTYL-talk to you later 1 #include 2 // FIXME include the string Library 3 using namespace std; 4 5 int main() { 6 7 8 9 10 } /* Type your code here. */ return 0; main.cpp
Consider the set A = {1, 2, 11, {121}, 22, 1212, (111, 212, 112}} Enter the value of Al. (Note: Enter a number).
Can this python code be done without using the isdigit() function. Please try to change the following code in the picture so it doesn't use isdigit().
Complete the rotate_text() function that takes 2 parameters, a string data and an integer n. If n is positive, then the function will shift all the characters in data forward by n positions, with characters at the end of the string being moved to the start of the string. If n is 0 then the text remains the same. For example: rotate_text('abcde', rotate_text('abcde', rotate_text('abcde', 1) would return the string 'eabcd' 3) would return the string 'cdeab' 5) would return the string 'abcde' rotate_text('abcde', 6) would return the string 'eabcd' ... and so on. If n is negative, then the function will shift the characters in data backward by n positions, with characters at the start of the string being moved to the end of the string. For example: rotate text('abcde', -1) would return the string 'bcdea'
Revorse the vewels def reverse_vowels(text): Given a text string, create and return a new string constructed by finding all its vowels (for simplicity, in this problem vowels are the letters found in the string 'aeiouAEIOU') and reversing their order, while keeping all other characters exactly as they were in their original positions. However, to make the result look prettier, the capitalization of each moved vowel must be the same as that of the vowel that was originally in the target position. For example, reversing the vowels of 'Ilkka' should produce 'Alkki' instead of 'alkkI'. Applying this operation to random English sentences seems to occasionally give them a curious pseudo-Mediterranean vibe.Along with many possible other ways to perform this square dance, one straightforward way to reverse the vowels starts with collecting all vowels of text into a separate list, and initializing the result to an empty string. After that, iterate through all positions of the original text.…
PYTHON Complete the function below, which takes two arguments: data: a list of tweets search_words: a list of search phrases The function should, for each tweet in data, check whether that tweet uses any of the words in the list search_words. If it does, we keep the tweet. If it does not, we ignore the tweet. data = ['ZOOM earnings for Q1 are up 5%', 'Subscriptions at ZOOM have risen to all-time highs, boosting sales', "Got a new Mazda, ZOOM ZOOM Y'ALL!", 'I hate getting up at 8am FOR A STUPID ZOOM MEETING', 'ZOOM execs hint at a decline in earnings following a capital expansion program'] Hint: Consider the example_function below. It takes a list of numbers in numbers and keeps only those that appear in search_numbers. def example_function(numbers, search_numbers): keep = [] for number in numbers: if number in search_numbers(): keep.append(number) return keep def search_words(data, search_words):
def findOccurrences(s, ch): lst = [] for i in range(0, len(s)): if a==s[i]: lst.append(i) return lst Use the code above instead of enumerate in the code posted below. n=int(input("Number of rounds of Hangman to be played:")) for i in range(0,n): word = input("welcome!") guesses = '' turns = int(input("Enter the number of failed attempts allowed:")) def hangman(word): secrete_word = "-" * len(word) print(" the secrete word " + secrete_word) user_input = input("Guess a letter: ") if user_input in word: occurences = findOccurrences(word, user_input) for index in occurences: secrete_word = secrete_word[:index] + user_input + secrete_word[index + 1:] print(secrete_word) else: user_input = input("Sorry that letter was not found, please try again: ") def findOccurrences(s, ch): return [i for i, letter in enumerate(s) if letter == ch] *** enumerate not discussed in…

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