Geometry and Reflections < 1 of 22 > Constants Learning Goal: To learn and practice the geometry skills necessary for complex reflection setups. • Part B Now, find the angle es (shown in the new figure (Eigure 2) in terms of e. You can easily find es in terms of e, then just substitute your expression from Part A The law of reflection has the very simple form Express your answer in terms of 6, and any numerical angles. When entering numerical values, assume the value is in degrees, so just use the number "23" to indicate 23 degrees. where enidret is the angle between the normal and the incident ray and Bretected is the angle between the normal and the reflected ray. Although the law itself is easy to use, many realistic situations involve successive reflections from multiple surfaces. The law of reflection does not become any more complicated in such cases, but the geometry of the rays does become complicated. Consider the case of light shining onto a mirror, which is attached to another mirror at some angle a, as shown in the figure (Eigure 1). In this problem, we will find the angle at which light leaves the arrangement of two mirrors. >View Available Hint(s) O = 90 – 0, Previous Answers v Correct • Part C Now, find the angle e shown in the figure (Eigure 3in terms of e, and a . Express your answer in terms of 0,, a, and any numerical angles. - View Available Hint(s) • Hint 1. Angles in a triangle ? X•10" Figure O 3 of 3 > OL = 180 – 0, Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining The correct answer involves the variable a, which was not part of your answer. Part D Complete previous part(s)
Geometry and Reflections < 1 of 22 > Constants Learning Goal: To learn and practice the geometry skills necessary for complex reflection setups. • Part B Now, find the angle es (shown in the new figure (Eigure 2) in terms of e. You can easily find es in terms of e, then just substitute your expression from Part A The law of reflection has the very simple form Express your answer in terms of 6, and any numerical angles. When entering numerical values, assume the value is in degrees, so just use the number "23" to indicate 23 degrees. where enidret is the angle between the normal and the incident ray and Bretected is the angle between the normal and the reflected ray. Although the law itself is easy to use, many realistic situations involve successive reflections from multiple surfaces. The law of reflection does not become any more complicated in such cases, but the geometry of the rays does become complicated. Consider the case of light shining onto a mirror, which is attached to another mirror at some angle a, as shown in the figure (Eigure 1). In this problem, we will find the angle at which light leaves the arrangement of two mirrors. >View Available Hint(s) O = 90 – 0, Previous Answers v Correct • Part C Now, find the angle e shown in the figure (Eigure 3in terms of e, and a . Express your answer in terms of 0,, a, and any numerical angles. - View Available Hint(s) • Hint 1. Angles in a triangle ? X•10" Figure O 3 of 3 > OL = 180 – 0, Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining The correct answer involves the variable a, which was not part of your answer. Part D Complete previous part(s)
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Homework 5: Geometric Optics**
**Geometry and Reflections**
**Learning Goal:**
To learn and practice the geometry skills necessary for complex reflection setups.
The law of reflection has the very simple form:
\[ \theta_{\text{incident}} = \theta_{\text{reflected}} \]
where \(\theta_{\text{incident}}\) is the angle between the normal and the incident ray and \(\theta_{\text{reflected}}\) is the angle between the normal and the reflected ray. Although the law itself is easy to use, many realistic situations involve successive reflections from multiple surfaces. The law of reflection does not become any more complicated in such cases, but the geometry of the rays does become complicated. Consider the case of light shining onto a mirror, which is attached to another mirror at some angle, as shown in the figure (Figure 1). In this problem, we will find the angle at which light leaves the arrangement of two mirrors.
**Part B**
Now, find the angle \(\theta_3\) (shown in the new figure (Figure 2)) in terms of \(\theta_1\). You can easily find \(\theta_3\) in terms of \(\theta_2\), then just substitute your expression from Part A.
Express your answer in terms of \(\theta_1\) and any numerical angles. When entering numerical values, assume the value is in degrees, so just use the number "23" to indicate 23 degrees.
\[ \theta_3 = 90 - \theta_1 \]
**Correct**
**Part C**
Now, find the angle \(\theta_4\) shown in the figure (Figure 3) in terms of \(\theta_1\) and \(\alpha\).
Express your answer in terms of \(\theta_1\), \(\alpha\), and any numerical angles.
*Hint 1: Angles in a triangle*
An incorrect attempt:
\[ \theta_4 = 180 - \theta_1 \]
**Incorrect; Try Again; 4 attempts remaining**
The correct answer involves the variable \(\alpha\), which was not part of your answer.
**Graph/Diagram Description:**
The diagram shows the reflection of light between two mirrors forming various angles. In Figure 3, angles \(\theta_1\), \(\theta_2\), and \(\theta_4\](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd88ac793-2950-49a0-adce-9c0a0e059b36%2Fb69f7447-ee54-4982-8afb-a975ba996d46%2Fh5ju3lh_processed.png&w=3840&q=75)
Transcribed Image Text:**Homework 5: Geometric Optics**
**Geometry and Reflections**
**Learning Goal:**
To learn and practice the geometry skills necessary for complex reflection setups.
The law of reflection has the very simple form:
\[ \theta_{\text{incident}} = \theta_{\text{reflected}} \]
where \(\theta_{\text{incident}}\) is the angle between the normal and the incident ray and \(\theta_{\text{reflected}}\) is the angle between the normal and the reflected ray. Although the law itself is easy to use, many realistic situations involve successive reflections from multiple surfaces. The law of reflection does not become any more complicated in such cases, but the geometry of the rays does become complicated. Consider the case of light shining onto a mirror, which is attached to another mirror at some angle, as shown in the figure (Figure 1). In this problem, we will find the angle at which light leaves the arrangement of two mirrors.
**Part B**
Now, find the angle \(\theta_3\) (shown in the new figure (Figure 2)) in terms of \(\theta_1\). You can easily find \(\theta_3\) in terms of \(\theta_2\), then just substitute your expression from Part A.
Express your answer in terms of \(\theta_1\) and any numerical angles. When entering numerical values, assume the value is in degrees, so just use the number "23" to indicate 23 degrees.
\[ \theta_3 = 90 - \theta_1 \]
**Correct**
**Part C**
Now, find the angle \(\theta_4\) shown in the figure (Figure 3) in terms of \(\theta_1\) and \(\alpha\).
Express your answer in terms of \(\theta_1\), \(\alpha\), and any numerical angles.
*Hint 1: Angles in a triangle*
An incorrect attempt:
\[ \theta_4 = 180 - \theta_1 \]
**Incorrect; Try Again; 4 attempts remaining**
The correct answer involves the variable \(\alpha\), which was not part of your answer.
**Graph/Diagram Description:**
The diagram shows the reflection of light between two mirrors forming various angles. In Figure 3, angles \(\theta_1\), \(\theta_2\), and \(\theta_4\
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