Problem #7 Given the light fixture on the picture. In this device you will be able to change the beam angle from 5 to 60 degrees. Assume an isometric distribution of the light on the illuminated surface 1) If the distance to the floor is 3 meters, what will be the beam Beam angle that will produce an Illuminated surface Diameter of 2 meters? 2) Angle (4) If the lamp is an LED lamp with a nominal power consumption of 20 watts, what will be the illuminance on the illuminated circle? Illuminated Surface Diameter Light Fixture Distance-
Problem #7 Given the light fixture on the picture. In this device you will be able to change the beam angle from 5 to 60 degrees. Assume an isometric distribution of the light on the illuminated surface 1) If the distance to the floor is 3 meters, what will be the beam Beam angle that will produce an Illuminated surface Diameter of 2 meters? 2) Angle (4) If the lamp is an LED lamp with a nominal power consumption of 20 watts, what will be the illuminance on the illuminated circle? Illuminated Surface Diameter Light Fixture Distance-
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Transcribed Image Text:**Problem #7**
*Description:*
Given the light fixture in the picture, you can change the beam angle from 5 to 60 degrees. Assume an isometric distribution of the light on the illuminated surface.
*Diagram Explanation:*
- The diagram features a light fixture emitting light in a conical shape.
- The central angle of the cone is labeled as the "Beam Angle (φ)."
- The distance from the light fixture to the floor is indicated as the "Light Fixture Distance."
- The base of the cone, where the light meets the floor, is labeled as the "Illuminated Surface Diameter."
*Questions:*
1. If the distance to the floor is 3 meters, what will be the beam angle that produces an illuminated surface with a diameter of 2 meters?
2. If the lamp is an LED lamp with a nominal power consumption of 20 watts, what will be the illuminance on the illuminated circle?
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