In Figure (a), a beam of light in material 1 is incident on a boundary at an angle of e, = 30°. The extent of refraction of the light into material 2 depends, in part, on the index of refraction n2 of material 2. Figure (b) gives the angle of refraction 02 versus n2 for a range of possible n2 values. The vertical axis scale is set by O2g = 18° and e26 = 42°. (a) What is the index of refraction of material 1? (b) If the incident angle is changed to 80° and material 2 has n2 = 2.8, then what is angle 02? 30 1.3 1.5 1.7 1.9 (a) (b) (a) Number i Units (b) Number i Units

icon
Related questions
Question
100%
Current Attempt in Progress
In Figure (a), a beam of light in material 1 is incident on a boundary at an angle of 0, = 30°. The extent of refraction of the light into
material 2 depends, in part, on the index of refraction n2 of material 2. Figure (b) gives the angle of refraction 02 versus n2 for a range of
possible n2 values. The vertical axis scale is set by 02g = 18° and 02b = 42°. (a) What is the index of refraction of material 1? (b) If the
incident angle is changed to 80° and material 2 has n2 = 2.8, then what is angle 02?
30
"1.3
1.5
1.7
1.9
(a)
(b)
(a) Number
i
Units
(b) Number
i
Units
eTextbook and Media
Transcribed Image Text:Current Attempt in Progress In Figure (a), a beam of light in material 1 is incident on a boundary at an angle of 0, = 30°. The extent of refraction of the light into material 2 depends, in part, on the index of refraction n2 of material 2. Figure (b) gives the angle of refraction 02 versus n2 for a range of possible n2 values. The vertical axis scale is set by 02g = 18° and 02b = 42°. (a) What is the index of refraction of material 1? (b) If the incident angle is changed to 80° and material 2 has n2 = 2.8, then what is angle 02? 30 "1.3 1.5 1.7 1.9 (a) (b) (a) Number i Units (b) Number i Units eTextbook and Media
Expert Solution
Step 1

Given, 

a.

θ1= 30°Using Snells Law we have,n1sin θ1= n2 sin θ2If angle θ1=θ2Then n1=n2From given figure we have θ1= 30°From Figure @ we observe  at θ2= 30 ° refractive index n2=1.7Hence the refractive index of the material 1, n1=n2=1.7

As Refractive Index has no units so, the required Refractive Index is 1.7

 

steps

Step by step

Solved in 2 steps

Blurred answer
Similar questions