Genetics/Chi Square Question: Should I accept or reject the null hypothesis. Why?

Human Anatomy & Physiology (11th Edition)
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Chapter1: The Human Body: An Orientation
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Genetics/Chi Square Question: Should I accept or reject the null hypothesis. Why?
II.
CHI-SQUARE
Transpose: x- 0.01
1. The student tested the hypothesis that a dumpy wing is inherited as a recessive trait by
performing X
a. What ratio did the student hypothesize?
b. Did the X' analysis support the hypothesis?
c. What do the data suggest about the dumpy mutation?
-0.009 (2.77)
= -0.005949880668
4.19
1= 0.009 (2.77)+ 0.01
4. 19
The student hypothesized that the F2 data (792:208) fit Mendel's 3:1 monohybrid ratio for recessive
= -0.005949880668 + 0.01
genes.
= 0.004
d?
= 0.004 < 0.005
Еxpected
ratio
Deviation (O-
E)
Deviation
(d)
= the null hypothesis
Observed (O)
Expected (E)
(3/4)
(1/4)
792-750 = 42 (42) = 1764
208-250 = -42(-42) = 1764
792
750
1764/750 = 2.35
250
|208
1764/250 =
7.056 or 7,06
X' = 9.41
Total = 1000
P=
0.004050119332
or 0.004
dt- 2-1 = 1
6.64
0.01
9.41
10.83
0.001
10.83 – 6.64
0.001 – 0.01
9.41 - 6.64
x- 0.01
4.19
-0.009
2.77
х- 0.01
Transcribed Image Text:II. CHI-SQUARE Transpose: x- 0.01 1. The student tested the hypothesis that a dumpy wing is inherited as a recessive trait by performing X a. What ratio did the student hypothesize? b. Did the X' analysis support the hypothesis? c. What do the data suggest about the dumpy mutation? -0.009 (2.77) = -0.005949880668 4.19 1= 0.009 (2.77)+ 0.01 4. 19 The student hypothesized that the F2 data (792:208) fit Mendel's 3:1 monohybrid ratio for recessive = -0.005949880668 + 0.01 genes. = 0.004 d? = 0.004 < 0.005 Еxpected ratio Deviation (O- E) Deviation (d) = the null hypothesis Observed (O) Expected (E) (3/4) (1/4) 792-750 = 42 (42) = 1764 208-250 = -42(-42) = 1764 792 750 1764/750 = 2.35 250 |208 1764/250 = 7.056 or 7,06 X' = 9.41 Total = 1000 P= 0.004050119332 or 0.004 dt- 2-1 = 1 6.64 0.01 9.41 10.83 0.001 10.83 – 6.64 0.001 – 0.01 9.41 - 6.64 x- 0.01 4.19 -0.009 2.77 х- 0.01
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