Gases: Out of exhaustion due to this problem set [including the problem sets in GPHY202] you exhaled a breath of air that is primarily consists of 74.8% N2, 15.3% O2, 3.7% CO2, and 6.2% water vapor [assuming that your breath is fresh]. (a) If the total pressure of the gas is 0.985 atm, calculate the partial pressure of each component of your exhausted breath. (b) If the volume is exhaled breath (gas) is 455 ml. and its temperature is 37 °C, calculate the number of moles of exhaled CO2. (c) How many grams of glucose (C6H1206) would need to be metabolized to produce this quantity of CO2? Please refer to the chemical reaction below: C,H1206 (aq) + 6 02(g) → 6 CO2 + 6 H20 (1)

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Chapter1: Chemical Foundations
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4. Gases: Out of exhaustion due to this problem set [including the problem sets in GPHY202] you exhaled
a breath of air that is primarily consists of 74.8% N2, 15.3% O2, 3.7% CO2, and 6.2% water vapor
[assuming that your breath is fresh]. (a) If the total pressure of the gas is 0.985 atm, calculate the partial
pressure of each component of your exhausted breath. (b) If the volume is exhaled breath (gas) is 455 ml
and its temperature is 37 °C, calculate the number of moles of exhaled CO2. (c) How many grams of
glucose (C6H1206) would need to be metabolized to produce this quantity of CO2? Please refer to the
chemical reaction below:
C,H1206 (aq) + 6 02(g) → 6 CO2 + 6 H20 (l)
Transcribed Image Text:4. Gases: Out of exhaustion due to this problem set [including the problem sets in GPHY202] you exhaled a breath of air that is primarily consists of 74.8% N2, 15.3% O2, 3.7% CO2, and 6.2% water vapor [assuming that your breath is fresh]. (a) If the total pressure of the gas is 0.985 atm, calculate the partial pressure of each component of your exhausted breath. (b) If the volume is exhaled breath (gas) is 455 ml and its temperature is 37 °C, calculate the number of moles of exhaled CO2. (c) How many grams of glucose (C6H1206) would need to be metabolized to produce this quantity of CO2? Please refer to the chemical reaction below: C,H1206 (aq) + 6 02(g) → 6 CO2 + 6 H20 (l)
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