da G) = G )) + G)dtWhat is the general solution of inhomogeneous state space equations?Eigenvectors.) = ), v. = C) = ()V2 generalized sigenvector.x1(t) = C, e¬t + C2 (t + 1) e¬t + 4x2(t) = C, e¬t + C2 t e=t + 3b)x1(t) = C, e¬t + C2 (t – 1) e¬t + 2x2(t) = C, e¬t + C2 t e¬t + 1x1(t) = C, e¬t + C2 (t – 1) e¬t –- 2x2(t) = -C e¬t - C2 te¬t + 7d)x1(t) = C, e¬t + C2t e¬t + 7x2(t) = 2 C, e¬t + C2 (2 t – 1) e-t + 10x1(t) = C, e¬t + C2 (t + 1) e¬t + 8x2(t) = -C e¬tCz t e=t3x1 (t) = C, e¬t + C2t e¬t - 1x2(t) = 2 C, e¬t + C2 (2 t + 1) e¬t - 6

Answered: Image /qna-images/answer/20ab8504-7c48-4faf-a0f6-fd89ac2b069d.jpg

* G) - G )G) + (;) d dt What is the general solution of inhomogeneous state space equations? Eigenvectors. V, = C) = G,), v. = CH) = () V2 generalized eigenvector. a) x1(t) = C, e¬t + C2 (t + 1) e¬t + 4 x2(t) = C, e¬t + C2te=t + 3 b) x1(t) = C, e¬t + C2 (t – 1) e¬t + 2 x2(t) = C, e¬t + Cz t e¬t + 1 x1(t) = C, e¬t + C2 (t – 1) e¬t – 2 x2(t) = -C, e¬t - C2 t e¬t + 7 %3D d) x1 (t) = C, e¬t + Czte¬t + 7 x2(t) = 2 C, e¬t + C2 (2 t – 1) e-t + 10 x1(t) = C, e¬t + C2 (t + 1) e¬t + 8 x2(t) = -C, e¬t - C2 te¬t – 3 x1 (t) = C, e=t + C2te¬t - 1 x2(t) = 2 C, e¬t + C2 (2 t + 1) e¬t - 6

* G) - G )G) + (;) d dt What is the general solution of inhomogeneous state space equations? Eigenvectors. V, = C) = G,), v. = CH) = () V2 generalized eigenvector. a) x1(t) = C, e¬t + C2 (t + 1) e¬t + 4 x2(t) = C, e¬t + C2te=t + 3 b) x1(t) = C, e¬t + C2 (t – 1) e¬t + 2 x2(t) = C, e¬t + Cz t e¬t + 1 x1(t) = C, e¬t + C2 (t – 1) e¬t – 2 x2(t) = -C, e¬t - C2 t e¬t + 7 %3D d) x1 (t) = C, e¬t + Czte¬t + 7 x2(t) = 2 C, e¬t + C2 (2 t – 1) e-t + 10 x1(t) = C, e¬t + C2 (t + 1) e¬t + 8 x2(t) = -C, e¬t - C2 te¬t – 3 x1 (t) = C, e=t + C2te¬t - 1 x2(t) = 2 C, e¬t + C2 (2 t + 1) e¬t - 6

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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