g= 6.67 ✕ 10−11 N · m2/kg2. m1= .1 m2= .19 r=.525 Using the formula F = Gm1m2 r2 with the value of G above, plus the masses and distance given above, the magnitude of the force (in N) is then (A) F = ___________ Let's compare this to the weight (in N) of the book—that is, the gravitational force on the book due to the Earth. Using the formula w = mg, we find the following. (B) w = _________N Notice that the gravitational force on the book due to the Earth is huge compared to the gravitational force on the book by the mouse. We can calculate how much larger by finding the ratio of these two forces. w F = (c) ________times larger This means that gravity is actually a very weak force. It requires a large amount of mass (like that of a planet) to be noticeable. The gravitational forces between ordinary objects in everyday life are typically so small that we can ignore them.
g= 6.67 ✕ 10−11 N · m2/kg2. m1= .1 m2= .19 r=.525 Using the formula F = Gm1m2 r2 with the value of G above, plus the masses and distance given above, the magnitude of the force (in N) is then (A) F = ___________ Let's compare this to the weight (in N) of the book—that is, the gravitational force on the book due to the Earth. Using the formula w = mg, we find the following. (B) w = _________N Notice that the gravitational force on the book due to the Earth is huge compared to the gravitational force on the book by the mouse. We can calculate how much larger by finding the ratio of these two forces. w F = (c) ________times larger This means that gravity is actually a very weak force. It requires a large amount of mass (like that of a planet) to be noticeable. The gravitational forces between ordinary objects in everyday life are typically so small that we can ignore them.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Let's continue our calculation of the gravitational force between the computer mouse and the book from the previous part.
g= 6.67 ✕ 10−11 N · m2/kg2.
m1= .1
m2= .19
r=.525
Using the formula
F =
with the value of G above, plus the masses and distance given above, the magnitude of the force (in N) is thenGm1m2 |
r2 |
(A) F = ___________
Let's compare this to the weight (in N) of the book—that is, the gravitational force on the book due to the Earth. Using the formula
w = mg,
we find the following.(B) w = _________N
Notice that the gravitational force on the book due to the Earth is huge compared to the gravitational force on the book by the mouse. We can calculate how much larger by finding the ratio of these two forces.
w |
F |
This means that gravity is actually a very weak force. It requires a large amount of mass (like that of a planet) to be noticeable. The gravitational forces between ordinary objects in everyday life are typically so small that we can ignore them.
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