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Combining the circular motion with Newton's Universal Gravitation Law, we have the following formula: v=NGMr, rearrange this formula and calculate the mass of Mars in kilograms rounded to 2 significant figures considering the values for the circular speed and distance of 2.14.103 m/s. a. M=v2•rG;M=6.4×1023 kg b. M=vrG;M=3.0×1020 kg c. M=v2Gr;M=4.1×10-11 kg d. M=v2rG; M=3.6×103 kg

Combining the circular motion with Newton's Universal Gravitation Law, we have the following formula: v=NGMr, rearrange this formula and calculate the mass of Mars in kilograms rounded to 2 significant figures considering the values for the circular speed and distance of 2.14.103 m/s. a. M=v2•rG;M=6.4×1023 kg b. M=vrG;M=3.0×1020 kg c. M=v2Gr;M=4.1×10-11 kg d. M=v2rG; M=3.6×103 kg

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Combining the circular motion with Newton’s Universal Gravitation Law, we have the following formula: ?=√???, rearrange this formula and calculate the mass of Mars in kilograms rounded to 2 significant figures considering the values for the circular speed and distance of 2.14.103 m/s.

Combining the circular motion with Newton's Universal Gravitation Law, we have the following formula: v=VGMP, rearrange this formula and calculate the mass of Mars in kilograms rounded to 2 significant figures considering the values for the circular speed and distance of 2.14.103 m/s. a. M=v2-rG;M=6.4×1023 kg b. M=vrG;M=3.0×1020 kg c. M=v2Gr;M=4.1×10-11 kg d. M=v2rG; M=3.6×103 kg
Transcribed Image Text:Combining the circular motion with Newton's Universal Gravitation Law, we have the following formula: v=VGMP, rearrange this formula and calculate the mass of Mars in kilograms rounded to 2 significant figures considering the values for the circular speed and distance of 2.14.103 m/s. a. M=v2-rG;M=6.4×1023 kg b. M=vrG;M=3.0×1020 kg c. M=v2Gr;M=4.1×10-11 kg d. M=v2rG; M=3.6×103 kg
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